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earnstyle [38]
1 year ago
12

Which original VPN protocol is supported by most platforms but offers low levels of security?

Computers and Technology
1 answer:
Masja [62]1 year ago
7 0

Answer:

vpn

Explanation:

PPTP is the least secure. ...

L2TP/IPsec is a good VPN solution for non-critical use; however, this protocol, like PPTP, has been compromised as well. ...

Across many areas of the IT world, OpenVPN is easily the best all-around VPN solution.

You might be interested in
Use HTML and CSS, create a web page for the table shown below. Please copy (and paste) your code from your text editor (Replit).
kenny6666 [7]
This is big sorry I can’t do it
6 0
2 years ago
An access control system that grants users only those rights necessary for them to perform their work is operating on which secu
solmaris [256]

Answer:

B. Least privilege                

Explanation:

  • The principle of least privilege an important principle in computer security.
  • It limits the access rights for users and only grant them with the rights that are sufficient for them to perform their required task.
  • For example a user is granted privilege to execute a file or manipulate data or use only the resources that are required for them to perform a particular task.
  • This principle can be used only to limit and control access rights to system resources and applications.
  • The least privilege is beneficial as it reduces the risk of unauthorized access.
  • For example a user whose task is data entry and has nothing to do with controlling access or granting access rights to users, will only be allowed to enter data to the DB by the principle of least privilege.
7 0
3 years ago
I am having trouble with this python question. I am in a beginner level class also so any solution that isn't too complex would
Delicious77 [7]

The code:

filename = input("> ")

with open(filename, "r") as file:

   items = file.read()

   items = items.split("\n")

   for index, item in enumerate(items):

       items[index] = item.split("\t")

   for item in items:

       if item[3] == "Available":

           print(f"{item[1]} ({item[0]}) -- {item[2]}")

Explenation:

1. We make the user enter the file's path, in our case "food.txt". This does only work if the .txt file is in the <u>same</u> directory as our code.

2. We get the content of our .txt file with the "open" function. If we use the "open" function inside of a "with" statement we don't have to deal with closing the file after we opened it. The file will close as soon as we exit the statement. The argument "r" indicates that we only want to read the file, not do anything else with it.

3. However the variable "file" doesn't contain the <u>contents</u> of "food.txt", only the class object of our file (if you try "print(file)" you'll only get nonsense). We can simply get the content of the file by calling ".read()" after.

4. We can separate this long str using the ".split()" function. The split function seperates a string by another sertain string (in our case "\n", since the different items are seperated by a newline). Now "items" is a list of strings.

5. Next we go through all items in "items" and separate them by "\t", again using the ".split()" function. Enumerate makes a list of indexes and values from another list (in our case, "items").

6. Now we have a list of lists of strings. The only thing left to do is go through every item and print it if the item's third item is equal to "Available" (notice that this is case-sensative). And print out the result in the desired format.

The code works for me, please ask me if there is anything you don't understand (or if the code is incorrect). Happy to help :D

5 0
2 years ago
The average pH of citrus fruits is 2.2, and this value has been stored in the variable avg_citrus_pH . Provide a statement to di
olasank [31]

Answer:

The statement in Python is:

print("The average pH of citrus fruits is ",avg_citrus_pH)

Java

System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);

C++

cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;

Explanation:

The programming language is not stated; so, I answered the question in 3 languages (Python, Java and C++)

Assume that avg_citrus_pH has been declared and initialized; all you need to do is invoke a print statement and then append the variable

In Python, use print()

In c++, use cout<<

In Java, use System.out.print()

So, the statements are:

Python:

print("The average pH of citrus fruits is ",avg_citrus_pH)

Java

System.out.print("The average pH of citrus fruits is "+avg_citrus_pH);

C++

cout<<"The average pH of citrus fruits is "<<avg_citrus_pH;

8 0
2 years ago
Write a c program to count the total number of commented characters and words in a c file taking both types of c file comments (
Tanzania [10]

#include<stdio.h>

#include<stdlib.h>

int comment1(FILE *fp)

{

   char ch;

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='\n')

       {

           return count;

       }

       count++;

   }

   return count;

}

int comment2(FILE *fp)

{

   char ch;

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='*')

       {

           fscanf(fp,"%c",&ch);

           if(ch=='/')

           {

               return count;

           }

           count++;

       }

       count++;

   }

   return 0;

}

int main()

{

   printf("Enter the file name:");

   char s[1000],ch,ch1;

   scanf("%s",s);

   FILE*fp;

   fp = fopen(s,"r");

   int count=0;

   while(fscanf(fp,"%c",&ch)!=EOF)

   {

       if(ch=='\"')

       {

           while(fscanf(fp,"%c",&ch)!=EOF)

           {

               if(ch=='\"')

               {

                   break;

               }

               if(ch=='\\')

               {

                   fscanf(fp,"%c",&ch);

               }

           }

       }

       else if(ch=='/')

       {

           fscanf(fp,"%c",&ch);

           if(ch=='/')

           {

               count += comment1(fp);

           }

           else if(ch=='*')

           {

               count += comment2(fp);

           }

       }

   }

   printf("%d\n",count);

   return 0;    

}

3 0
3 years ago
Read 2 more answers
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