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rusak2 [61]
2 years ago
13

What are the 3 dimension of an information system?

Computers and Technology
1 answer:
Ne4ueva [31]2 years ago
3 0

Answer:

There are three dimensions of information systems ; organizational, management, and technology. Senior management always make decisions, so senior management is required to understand these three dimensions to make better decisions of the business through information systems.

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Management of software development consist of?
JulsSmile [24]

Answer:

d. All of the above

Explanation:

A software can be defined as a set of executable instructions (codes) or collection of data that is used typically to instruct a computer how to perform a specific task and to solve a particular problem.

A software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications.

In Computer science, management of software development consist of;

a. Process: it involves the stages through which a software application is analyzed, designed, developed, tested, etc.

b. People: it refers to the individuals involved in the software development process.

c. Project: it's the entirety of the stages a software goes through before it gets to the end user.

5 0
3 years ago
The amount of data that can be stored on a disk depends in part on_____.
MariettaO [177]
To what it seems like, it’s d
8 0
2 years ago
[1] Please find all the candidate keys and the primary key (or composite primary key) Candidate Key: _______________________ Pri
AVprozaik [17]

Answer:

Check the explanation

Explanation:

1. The atomic attributes can't be a primary key because the values in the respective attributes should be unique.

So, the size of the primary key should be more than one.

In order to find the candidate key, let the functional dependencies be obtained.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

Closure of attribute { Emp_ID, Date_Completed } is { Emp_ID, Date_Completed , Name, DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Name , Date_Completed } is { Name, Date_Completed , Emp_ID , DeptID, Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { DeptID, Date_Completed } is { DeptID, Date_Completed , Emp_ID,, Name, , Marketing, Salary, Course_Name, Course_ID}

Closure of attribute { Marketing, Date_Completed } is { Marketing, Date_Completed , Emp_ID,, Name, DeptID , Salary, Course_Name, Course_ID}.

So, the candidate keys are :

{ Emp_ID, Date_Completed }

{ Name , Date_Completed }

{ DeptID, Date_Completed }

{ Marketing, Date_Completed }

Only one candidate key can be a primary key.

So, the primary key chosen be { Emp_ID, Date_Completed }..

2.

The functional dependencies are :

Emp_ID -> Name, DeptID, Marketing, Salary

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

Course_ID -> Course Name

Course_Name ->  Course_ID

Date_Completed -> Course_Name

3.

For a relation to be in 2NF, there should be no partial dependencies in the set of functional dependencies.

The first F.D. is

Emp_ID -> Name, DeptID, Marketing, Salary

Here, Emp_ID -> Salary ( decomposition rule ). So, a prime key determining a non-prime key is a partial dependency.

So, a separate table should be made for Emp_ID -> Salary.

The tables are R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

and R2( Emp_ID , Salary)

The following dependencies violate partial dependency as a prime attribute -> prime attribute :

Name -> Emp_ID

DeptID -> Emp_ID

Marketing ->  Emp_ID

The following dependencies violate partial dependency as a non-prime attribute -> non-prime attribute :

Course_ID -> Course Name

Course_Name ->  Course_ID

So, no separate tables should be made.

The functional dependency Date_Completed -> Course_Name has a partial dependency as a prime attribute determines a non-prime attribute.

So, a separate table is made.

The final relational schemas that follows 2NF are :

R1(Emp_ID, Name, DeptID, Marketing, Course_ID, Course_Name, Date_Completed)

R2( Emp_ID , Salary)

R3 (Date_Completed, Course_Name, Course_ID)

For a relation to be in 3NF, the functional dependencies should not have any transitive dependencies.

The functional dependencies in R1(Emp_ID, Name, DeptID, Marketing, Date_Completed) is :

Emp_ID -> Name, DeptID, Marketing

This violates the transitive property. So, no table is created.

The functional dependencies in R2 (  Emp_ID , Salary) is :

Emp_ID -> Salary

The functional dependencies in R3 (Date_Completed, Course_Name, Course_ID) are :

Date_Completed -> Course_Name

Course_Name   ->  Course_ID

Here there is a transitive dependency as a non- prime attribute ( Course_Name ) is determining a non-attribute ( Course_ID ).

So, a separate table is made with the concerned attributes.

The relational schemas which support 3NF re :

R1(Emp_ID, Name, DeptID, Course_ID, Marketing, Date_Completed) with candidate key as Emp_ID.

R2 (  Emp_ID , Salary) with candidate key Emp_ID.

R3 (Date_Completed, Course_Name ) with candidate key Date_Completed.

R4 ( Course_Name, Course_ID ).  with candidate keys Course_Name and Course_ID.

6 0
3 years ago
The movement of the economy through highs and lows is referred to as:
skad [1K]

Answer:

the business cycle

Explanation:

5 0
3 years ago
Your location has been assigned the 172.149.254.0 /24 network. You are tasked with dividing the network into 13 subnets with the
ira [324]
  • The subnet mask would be a 32-bit integer which is formed by assigning the host bits to all 0's and the networking bits to so many 1's.
  • In this method, the subnetting separates the IP address between host and network addresses.
  • The subnet mask covers an IP address with its 32-bit number, thus the term "mask".

Given:

Network IP address \bold{= 172.149.254.0 /24}

Subnet numbers \bold{= 13}

Calculating the borrow bits:

\to  \bold{= ceil(\log_{2} 13) = 4 \ bits}

a)

Calculating the dotted decimal value for the subnet mask:

\to \bold{11111111.11111111.11111111.00000000}\\\\\to \bold{255.255.255.240}\\\\

b)

The additional bits which will be needed to mask the subnet mask that is = 4.

Learn more: brainly.com/question/2254014

4 0
3 years ago
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