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natulia [17]
3 years ago
7

What's the answer to this​

Computers and Technology
1 answer:
yarga [219]3 years ago
5 0

Answer:

S

Explanation:

The index operator will address individual characters in the string.

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the easiest and cheapest time to alter the information system is in the ________ phase of the sdlc. a. requirements analysis b.
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I would think its the "<span>requirements analysis" phase.

Because the </span>requirements analysis<span>,</span><span> is the process of determining user expectations for a new or modified product.</span>
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4 years ago
In what decade was photography invented? the 1800s the 1820s the 1840s the 1860s
frutty [35]

Answer:

In the year 1820's

It is B

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3 years ago
A certain computer has a 4meg address space. how many bits wide is this computer's address bus?
PIT_PIT [208]
22 bits






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4 0
3 years ago
Consider a set of mobile computing clients in a certain town who each
poizon [28]

Answer: answer given in the explanation

Explanation:

We have n clients and k-base stations, say each client has to be connected to a base station that is located at a distance say 'r'. now the base stations doesn't have allocation for more than L clients.

To begin, let us produce a network which consists of edges and vertex

Network (N) = (V,E)

where V = [S, cl-l, - - - -  cl-n, bs-l - - - - - - bs-k, t]

given that cl-l, - - - - - cl-n represents nodes for the clients

also we have that bs-l, - - - - - bs-k represents the nodes for base station

Also

E = [ (s, cl-i), (cl-i,bs-j), (bs-j,t)]

(s, cl-i) = have capacity for all cl-i (clients)

(cl-i,bs-j) = have capacity for all cl-i  clients & bs-j (stations)

⇒ using Fond Fulkorson algorithm we  find the max flow in N

⇒ connecting cl-i clients to  bs-j stations

      like (cl-i, bs-j) = 1

   if f(cl-i, bs-j)  = 0

⇒ say any connection were to produce a valid flow, then

if cl-i (clients) connected                f(s,cl-i) = 1 (o otherwise)

if cl-i (clients) connected  to bs-j(stations)   f(cl-i,bs-j) = 1 (o otherwise)

   f(bs-j,t) = no of clients  (cl-i)  connected to bs-j

⇒ on each node, the max flow value (f) is longer than the no of clients that can be connected.

⇒ create the connection between the client and base station i.e. cl-l to base bs-j iff    f(cl-i, bs-j) = 1

⇒ when considering the capacity, we see that any client cannot directly connect to the base stations, and also the base stations cannot handle more than L clients, that is because the load allocated to the base statsion is L.

from this, we say f is the max no of clients (cl-i) that can be connected if we find the max flow, we can thus connect the client to the base stations easily.

cheers i hope this helps

5 0
3 years ago
charles, a security analyst, needs to check his network for vulnerabilities. he wants a scan that interacts with network nodes a
finlep [7]

Charles, a security analyst, needs to check his network for vulnerabilities. he wants a scan that interacts with network nodes and repairs security issues found. The kind of scanning that best describes Charles's requirements is: Active scanning.

<h3>Who is a Security Analyst?</h3>

A Security Analyst's responsibilities include the following:

Define, plan, execute, maintain, and improve security measures, policies, and controls. Writing reports and offering insights on the effectiveness of current security policies, incident response plans, disaster recovery plans, and other security-related information

Active scanning is a scanning approach that involves scanning individual endpoints in an IT network in order to retrieve more specific information.

Learn more about Security Analysts:
brainly.com/question/16354463
#SPJ1

6 0
1 year ago
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