Answer:
Offset bits: 3-bits
Set number of cache: 12-bits
Tag bits: 7-bits
22-bit physical address
Explanation:
Since the system is 32K so,
=2⁵.2¹⁰
=2¹⁵
As we know that it is 8-way set associative so,
=2¹⁵/2³
=2¹⁵⁻³
=2¹²
2¹² are cache blocks
22-bit physical address
Off-set bits are 3 as they are calulated from 8-way set associative information.
Set number of cache : 12-bits
For tag-bits:
Add off-set bits and cache bits and subtract from the total bits of physical address.
=22 - (12+3)
=22 - 15
=7
Depending on the data all answers can be used to make it easier to read. Without more info I would go with Borders (D) since they are the best way to group the data when printed, especially if the print is in color.
Alignment would be the correct answer only if the data goes out of cell boundaries. Font Color usually makes it harder to read because of bad contrast and finally changing the Font Style has a minimal effect since the default one is already pretty readable.
