Answer:
Step-by-step explanation:
Given the equation of motion;
S = ut + 1/2 at² where;
u is the initial velocity,
a is the acceleration, and;
t is the time.
We are to express a in terms of u, t and S
Making a the subject of the formula;
S = ut + 1/2 at²
S-ut = 1/2at²
2(S-ut) = at²
a = 2(S-ut)/t²
Hence the acceleration a in terms of other variables is expressed as a = 2(S-ut)/t²
Answer:
There's not enough information...
Answer:
Step-by-step explanation:
plug all in
1) 0 when x=0
2) 1*6-1²=6-1=5
3) 6*2-2²=12-4=8
4)6*3-3²=18-9=9
5) 6*4-4²=24-16=8
6)6*5-5²=30-25=5
7) 6*6-6²=36-36=0
The distnace around a two dimensional shape
Answer:
3: 2q − 4 = 20
Step-by-step explanation:
Solve for q:
2 q - 4 = 20
Add 4 to both sides:
2 q + (4 - 4) = 4 + 20
4 - 4 = 0:
2 q = 20 + 4
20 + 4 = 24:
2 q = 24
Divide both sides of 2 q = 24 by 2:
(2 q)/2 = 24/2
2/2 = 1:
q = 24/2
The gcd of 24 and 2 is 2, so 24/2 = (2×12)/(2×1) = 2/2×12 = 12:
Answer: q = 12
