1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kiruha [24]
4 years ago
8

Find the value of x If 100x =265.0

Mathematics
2 answers:
kakasveta [241]4 years ago
8 0
To solve:

1) Divide both sides by 100

100x/100 = 265/100

x = 2.65
tresset_1 [31]4 years ago
5 0
X=2.65 basically divide 265 divided by 100
You might be interested in
A town has a population of 2000 and grows at 4.5% every year. What will be the
goldfiish [28.3K]

Answer:

3544

Step-by-step explanation:

This is a problem of compound growth. The formula is

F=P(1+r)^t

Where F is the value in the future (in this case, the population after 13 years)

P is the intial amount (here, the initial population of 2000, so P = 2000)

r is the rate of growth (here, it is 4.5%, in decimal, 0.045)

t is the time frame (here, it is 13 years, so t = 13)

<em>we can plug the numbers into the formula and solve for F:</em>

<em>F=P(1+r)^t\\F=2000(1+0.045)^{13}\\F=2000(1.045)^{13}\\F=3544.4</em>

<em>rounded to the nearest whole number, the </em><em>population after 13 years would be 3544</em>

3 0
3 years ago
Read 2 more answers
The sum of four consecutive whole numbers is 54, what are the four numbers
anastassius [24]
Let the four consecutive numbers be x, x+1, x+2, and x+3.

The sum of the four numbers is 54, therefore
x + (x+1) + (x+2) + (x+3) = 54
4x + 6 = 54
4x = 54 - 6 = 48
x = 12

Answer:
The four numbers are 12, 13, 14, and 15

7 0
3 years ago
Consider two people being randomly selected. (For simplicity, ignore leap years.)
inna [77]

Answer:

(a) = \frac{144}{133225} \\\\(b) = \frac{1}{365}

Step-by-step explanation:

Part (a) the probability that two people have a birthday on the 9th of any month.

Neglecting leap year, there are 365 days in a year.

There are 12 possible 9th in months that make a year calendar.

If two people have birthday on 9th; P(1st person) and P(2nd person).

=\frac{12}{365} X\frac{12}{365}  = \frac{144}{133225}

Part (b) the probability that two people have a birthday on the same day of the same month

P(2 people selected have birthday on the same day of same month) + P(2 people selected not having birthday on  same day of same month) = 1

P(2 people selected not having birthday on  same day of same month):

= \frac{365}{365} X \frac{364}{365} =\frac{364}{365}

P(2 people selected have birthday on the same day of same month) = 1-\frac{364}{365} \\\\= \frac{1}{365}

7 0
3 years ago
A retiree invests $5,000 in savings plan that pays 4% per year. What will the account balance be at the end of the first year ?
Ira Lisetskai [31]
$5000 + 4% = $5000.04
3 0
3 years ago
Read 2 more answers
What is 4 and 2/3 written as a radical?
TEA [102]

Answer:

14/3

Step-by-step explanation:

4 and 2/3 = 4 2/3 = 4 + 2/3 = 4/1 + 2/3 = 12/3 + 2/3 = 14/3

7 0
3 years ago
Other questions:
  • Write the name of the period that has the digits 208
    9·1 answer
  • The digit 5 in 357 represents 1 tenth as much as the digit 5 in 465
    11·1 answer
  • Car Value: In one year a new car decreased in value by 20%. If it sold for $19,400 when it was new, what was it worth after 1 ye
    12·1 answer
  • What is the answer to 5x-2y=30
    9·1 answer
  • 7. What is the perimeter of a square with side<br>lengths of 4 inches?<br>​
    11·1 answer
  • What is x(-14x + 9)?
    10·1 answer
  • Which of the followinng has zero width and an infinite lenght?
    6·1 answer
  • Which inequality is represented by the graph ??pls help:)?
    13·1 answer
  • KE= 0.5 .m.v2 OR PE= m.g.h Kinetic and Potential Energy Practice Problems. Solve the following problems and show your work! 1. A
    11·1 answer
  • Travis paid $27.50 for 11 pounds of grapes how much would travis pay for 4 pounds of grapes
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!