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Mamont248 [21]
4 years ago
6

Valuate the line integral, where c is the given curve. ∫c zdx + xdy + ydz

Mathematics
1 answer:
Semenov [28]4 years ago
3 0
\displaystyle\int_{\mathcal C}z\,\mathrm dx+x\,\mathrm dy+y\,\mathrm dz=\int_{\mathcal C}\langle z,x,y\rangle\cdot\mathrm d\langle x,y,z\rangle
\displaystyle=\int_{t=0}^{t=1}\langle t^2,t^2,t^3\rangle\cdot\mathrm d\langle t^2,t^3,t^2\rangle
=\displaystyle\int_0^1\langle t^2,t^2,t^3\rangle\cdot\langle2t,3t^2,2t\rangle\,\mathrm dt
=\displaystyle\int_0^15t^4+2t^3\,\mathrm dt=\frac32
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A month of the year is chosen at random. What is the probability that it has 31 days
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There are 12 months, 7/12 have 31 days. You would have a 7/12 probability of choosing one with 31 days if it is random.

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3 years ago
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Which graph represents f(x)=−2cos(4πx)?
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Answer:

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The roof of the building shown below has a span of 48 feet. The rafters upon which the roof is laid are 30 feet long, including
anyanavicka [17]

Solution :

Given :

Span of the roof = 48 feet

Length of the rafter = 30 feet (including the 4 feet overhung)

So, for the 30 feet long rafter, 26 feet will be rafter length from the high point of the roof to the edge of the roof and 4 feet will be the roof overhung.

Therefore, the horizontal span per rafter is

$=\frac{48}{2}$

= 24 feet

a). So the rise of the roof is $= \sqrt{(26)^2-(24)^2}$  

                                         = 10 feet

b). Pinch of the roof is $=\frac{\text{rise}}{\text{run}}$

                                     $=\frac{10}{24}$

                                     $=\frac{5}{12}$

c). The percent of the roof used as overhung is

     $=\frac{4+4}{60}\times 100$

     $=\frac{80}{6}$

       = 13.33 %

8 0
3 years ago
Three siblings are born on the same date in consecutive years.
Oduvanchick [21]

Answer:

C.

Step-by-step explanation:

15+14+13=42

Hope this helps :)

8 0
3 years ago
Use the principle of inclusion and exclusion to find the number of positive integers less than 1,000,000 that are not divisable
wel
This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.

∴N(c₁) = \frac{999,999}{6} = 166666
N(c₂) = \frac{999,999}{4} = 250000
∴N(c₁c₂) = \frac{999,999}{24} = 41667
∴ Number of positive integers that are not divisible by 4 or 6,

N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4
8 0
4 years ago
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