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Mamont248 [21]
3 years ago
6

Valuate the line integral, where c is the given curve. ∫c zdx + xdy + ydz

Mathematics
1 answer:
Semenov [28]3 years ago
3 0
\displaystyle\int_{\mathcal C}z\,\mathrm dx+x\,\mathrm dy+y\,\mathrm dz=\int_{\mathcal C}\langle z,x,y\rangle\cdot\mathrm d\langle x,y,z\rangle
\displaystyle=\int_{t=0}^{t=1}\langle t^2,t^2,t^3\rangle\cdot\mathrm d\langle t^2,t^3,t^2\rangle
=\displaystyle\int_0^1\langle t^2,t^2,t^3\rangle\cdot\langle2t,3t^2,2t\rangle\,\mathrm dt
=\displaystyle\int_0^15t^4+2t^3\,\mathrm dt=\frac32
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Answer: 2 1/3

Explanation:

10 2/6 - 7 5/6

You can make both a fraction by multiplying the denominator by the whole number, and then adding the numerator to that number, and keeping the denominator the same. So, 10*6 = 60 and 60 + 2 = 62 and you keep the denominator as 6, which would make 62/6

7*6 = 42 and 42 + 5 = 47 so 7 5/6 becomes 47/6

10 2/6 is equivalent to 62/6

7 5/6 is equivalent to 47/6

This just makes it easier to look at.

Now you just work through the equation.

62/6 - 47/6 = 15/6

15/6 = 2 3/6 = 2 1/3

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