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2 years ago

Need the answer to the question

Mathematics

1 answer:

Morgarella [4.7K]2 years ago

5 0

Answer:

The graph is wider and is reflected across the x axis.

Step-by-step explanation:

See attached image.

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A company ships packages through the postal service. One week, the cost of shipping one

DanielleElmas [232]

Answer:

Step-by-step explanation:

For this problem, it says that the company not only shipped packages, but also bought a number of stamps. From the equation 6.70+0.50x, it's fairly easy to say that 6.70 is the packages,

What's not so easy is figuring out whether or not 0.50 is the stamps, or x is. However, there's an easy way to figure it out!

From this one, we would have to use "common sense" (not my words, someone elses). Using "common sense", we have to think, can someone buy 0.50 of a stamp?

Technically yes... But would someone buy 0.5 of a stamp? Not really.

So we can safetly assume that x is the "stamp", and 0.50 is <em>the cost of the stamp</em>.

Hope this helps!

7 0

2 years ago

In 2016, London elected its first ________ mayor.

lapo4ka [179]

B. Muslim
Sadiq Kahn identifies as a Muslim.

6 0

3 years ago

What is the slope between point A (-9, 4) and B ( 3, -2)

MaRussiya [10]

Slope can be calculated using the formula: m= $\frac{y2 -y1}{x2-x1}$

y1/x1 represents the first number in the bracket

y2/x2 represents the second number in the bracket

Calculation

m = $\frac{y2 -y1}{x2-x1}$

m = $\frac{4 - (-2)}{(-9)-3}$

m= 6/-12

m= -0.5 or -1/2

Therefore, the answer is B.

5 0

3 years ago

Evaluate the sum of the following finite geometric series.

rjkz [21]

Answer:

$\large\boxed{\dfrac{156}{125}\approx1.2}$

Step-by-step explanation:

<h3>Method 1:</h3>

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}\\\\for\ n=1\\\\\left(\dfrac{1}{5}\right)^{1-1}=\left(\dfrac{1}{5}\right)^0=1\\\\for\ n=2\\\\\left(\dfrac{1}{5}\right)^{2-1}=\left(\dfrac{1}{5}\right)^1=\dfrac{1}{5}\\\\for\ n=3\\\\\left(\dfrac{1}{5}\right)^{3-1}=\left(\dfrac{1}{5}\right)^2=\dfrac{1}{25}\\\\for\ n=4\\\\\left(\dfrac{1}{5}\right)^{4-1}=\left(\dfrac{1}{5}\right)^3=\dfrac{1}{125}$

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}=1+\dfrac{1}{5}+\dfrac{1}{25}+\dfrac{1}{125}=\dfrac{125}{125}+\dfrac{25}{125}+\dfrac{5}{125}+\dfrac{1}{125}=\dfrac{156}{125}$

<h3>Method 2:</h3>

$\sum\limits_{n=1}^4\left(\dfrac{1}{5}\right)^{n-1}\to a_n=\left(\dfrac{1}{5}\right)^{n-1}\\\\\text{The formula of a sum of terms of a geometric series:}\\\\S_n=a_1\cdot\dfrac{1-r^n}{1-r}\\\\r-\text{common ratio}\to r=\dfrac{a_{n+1}}{a_n}\\\\a_{n+1}=\left(\dfrac{1}{5}\right)^{n+1-1}=\left(\dfrac{1}{5}\right)^n\\\\r=\dfrac{\left(\frac{1}{5}\right)^n}{\left(\frac{1}{5}\right)^{n-1}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\r=\left(\dfrac{1}{5}\right)^{n-(n-1)}=\left(\dfrac{1}{5}\right)^{n-n+1}=\left(\dfrac{1}{5}\right)^1=\dfrac{1}{5}$

$a_1=\left(\dfrac{1}{5}\right)^{1-1}=\left(\dfrac{1}{5}\right)^0=1$

$\text{Substitute}\ a_1=1,\ n=4,\ r=\dfrac{1}{5}:\\\\S_4=1\cdot\dfrac{1-\left(\frac{1}{5}\right)^4}{1-\frac{1}{5}}=\dfrac{1-\frac{1}{625}}{\frac{4}{5}}=\dfrac{624}{625}\cdot\dfrac{5}{4}=\dfrac{156}{125}$

5 0

3 years ago

Help me on B plz cant work it out

Nookie1986 [14]

Answer:

1kg = 1000g

400g = 0,4 kg

0,4 - 1

1 - n

multiply diagonally

0,4*n = 1

n=10/4=2,5

1:2,5 is correct answer

Step-by-step explanation:

6 0

3 years ago