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il63 [147K]
3 years ago
11

What does 4^8/4^-2 equal?

Mathematics
2 answers:
viva [34]3 years ago
8 0

Answer:

Hello there I'm Ashlynn It's lovely to meet you

___________________________________________

(4^8) / (4^(-2)) = 1, 048, 576

___________________________________________

<em>“Never give up, for that is just the place and time that the tide will turn.” – </em><em>Harriet Beecher Stowe</em>

Sonbull [250]3 years ago
4 0

Answer:

4^10 (base 4)

2^20 (base 2)

Step-by-step explanation:

Law of Exponent:

\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n} } =  {a}^{m - n}  }

Compare:

\displaystyle \large{ \frac{ {a}^{m} }{ {a}^{n} } = \frac{ {4}^{8} }{ {4}^{  - 2} }   }

  • a = 4
  • m = 8
  • n = -2

Therefore:

\displaystyle \large{  \frac{ {4}^{8} }{ {4}^{  - 2} }   =  {4}^{8 - ( - 2)}  } \\  \displaystyle \large{  \frac{ {4}^{8} }{ {4}^{  - 2} }   =  {4}^{8  + 2}  } \\  \displaystyle \large{  \frac{ {4}^{8} }{ {4}^{  - 2} }   =  {4}^{10}  }

Althought you didn't specific if I should leave answer as base 4 or base 2.

If you want the answer in base 2.

From:

\displaystyle \large{   {4}^{10}  =  { ({2}^{2}) }^{10}  }

Law of Exponent II

\displaystyle \large{  { ({a}^{m} )}^{n}   =  {a}^{m \times n}  }

Apply the law:

\displaystyle \large{   {4}^{10}  =  { ({2}^{2}) }^{10}  } \\  \displaystyle \large{   {4}^{10}  =  {2}^{20}  }

Thus, in base 2 form, it's 2^20

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