Answer:
f(x-4) = x²-8x + 17
f(x-4)-f(-4) = x²-8x
Step-by-step explanation:
Given the function:
f(x) = x^2+1
f(x-4) = (x-4)^2+1
f(x-4 ) = x² - 8x + 16 + 1
f(x-4) = x²-8x + 17
For f(x-4)-f(-4)
f(-4) = (-4)²+1
f(-4) = 16+1
f(-4) = 17
f(x-4)-f(-4) = x²-8x + 17 - 17
f(x-4)-f(-4) = x²-8x
Answer:
Yes, it is.
Step-by-step explanation:
Plz give me brainliest thank u
"h and k cannot both equal zero" -- yes, it can. if the vertex of a parabola is at (0, 0), there's nothing incorrect/invalid about that!!
"k and c have the same value" -- k and c do not have the same value. "k" is the y-value of the vertex and c is the constant in your quadratic equation, and the constant is not necessarily the y-value.
"the value of a remains the same" -- this is true. the a's in your equations are the same values, because the a-value is the coefficient of the x-variable in both equations. y = a(x - h)^2 and y = ax^2 -- both of these have a applying to your x-variables.
"h is equal to one half -b" -- this isn't true. the formula for calculating the x value of the vertex (h is the x-value of the vertex) is h = (-b/2a). -b/2a is not the same as one half -b because this answer choice doesn't involve the a-value.
Answer:
Can you please add a photo becauseI'm not sure how to help you out with this problem without context:)
Answer:
(2+6=8) and 12.3+19=21.3 hope this helps
Step-by-step explanation: