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3 years ago

What is the best difference between a line and a point

1 answer:

6 0

A line has one dimension which we call its length. A point has no dimensions. No length width or height. It's only a location.

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Compute P(X) using the binomial probability formula. Then determine whether the normal distribution can be used to estimate thi

MAXImum [283]

Answer and Step-by-step explanation: P(X) calculated by the binomial probability formula is:

P(X) = $\left[\begin{array}{ccc}n\\X\end{array}\right]$ . $p^{x}.(1-p)^{n-x}$

P(20) = $\left[\begin{array}{ccc}53\\20\end{array}\right] .(0.3)^{20}.(1-0.3)^{33}$

P(20) = $\frac{53!}{33!.20!}.3.5.10^{-11}.7.7.10^{-6}$

P(20) = 0.0552

To determine whether the normal distribution can be used to estimate this probability, both n.p and n.(1-p) must be greater than 5:

n . p = 53*0.3 = 15.9

n.(1-p) = 53(1-0.3) = 37.1

Since both ARE greater than 5, normal distribution can be used.

To approximate:

mean = n . p = 15.9

standard deviation = $\sqrt{n.p.(1-p)}$ = 3.34

Find the z-score:

z = $\frac{x - mean}{sd}$ = $\frac{20-15.9}{3.34} = 1.23$

z-score = 0.8907

Comparing values:

0.8907 - 0.0552 = 0.8355

6 0

3 years ago

Which ordered pairs are solutions to this system of inequalities?

Dafna11 [192]

9514 1404 393

Answer:

c, d, e

Step-by-step explanation:

The first two listed points are not in the solution set. The remaining three are.

Any point in the doubly-shaded area, or on the solid boundary line of that area is part of the solution set. Points (-1, -6), (0, -5), and (0.5, -2) are solutions to the given inequalities.

7 0

3 years ago

Write two decimals that are equivalent to 0.9

Maurinko [17]

0.90 and I think .9 is another I'm not sure but I tried

6 0

3 years ago

Read 2 more answers

Allison measured her rectangular deck and found that it has dimensions of

bogdanovich [222]

Answer:

Step-by-step explanation:

4 0

3 years ago

Simplify this expression: cos theta/ tan theta cot theta

Dmitry_Shevchenko [17]

Q: $\frac{cos\theta}{tan\theta.cot\theta}=?$

A:

$\frac{cos\theta}{tan\theta.cot\theta}=cos\theta$

because... $tan\theta.cot\theta=1$
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Q: $\frac{cos\theta}{tan\theta}.cot\theta=?$

A:

$\frac{cos\theta}{tan\theta}.cot\theta&= \\ \\ \frac{cos\theta}{\frac{sin\theta}{cos\theta}}.\frac{cos\theta}{sin\theta}&= \\ \\ \frac{cos^2\theta}{sin\theta}}.\frac{cos\theta}{sin\theta}&= \\ \\ \frac{cos^3\theta}{sin^2\theta}}&= cos^3\theta.cosec^2\theta$

5 0

4 years ago