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kiruha [24]
2 years ago
10

suppose you walk at the rate of 210 ft per minute you need to walk 10000 feet how many more minutes will it take you to finish i

f you have already walked 550 ft
Mathematics
2 answers:
lorasvet [3.4K]2 years ago
5 0

I am going to say 45 more minutes


aleksklad [387]2 years ago
3 0

Answer:

<em>45</em>

Step-by-step explanation:

You need to walk a total of 10,000 ft. You already walked 550 ft.

10,000 frt - 550 ft = 9,450 ft

You need to walk another 9,450 ft.

You walk at the rate of 210 ft per minute.

(9,450 ft)/(210 ft/min) = 45 minutes

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We know that Angle Bisector Divides an Angle into Two Equal Angles.

As UP is the Angle Bisector of Angle U, It Divides Angle U into two Equal Parts they are Angle(1) and Angle(2)

⇒ Angle(1) = Angle(2)

Given Angle(1) = 5x + 10 and Angle(2) = 3x + 14

⇒ 5x + 10 = 3x + 14

⇒ 2x = 4

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So : Measure of Angle(1) is 20

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I assume each path C is oriented positively/counterclockwise.

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\begin{cases} x(t) = 4\cos(t) \\ y(t) = 4\sin(t)\end{cases} \implies \begin{cases} x'(t) = -4\sin(t) \\ y'(t) = 4\cos(t) \end{cases}

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ds = \sqrt{x'(t)^2 + y'(t)^2} \, dt = \sqrt{16(\sin^2(t)+\cos^2(t))} \, dt = 4\,dt

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\displaystyle \int_C xy^4 \, ds = \int_{-\pi/2}^{\pi/2} (4\cos(t)) (4\sin(t))^4 (4\,dt) = 4^6 \int_{-\pi/2}^{\pi/2} \cos(t) \sin^4(t) \, dt

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