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GREYUIT [131]
3 years ago
6

If one-third of a number is greater than five less than twice the number, which of the following is true? x < 3, x > -3, x

> -3/5, x < 3/5
Mathematics
2 answers:
dem82 [27]3 years ago
5 0
The answer is gonna be x<3
Ghella [55]3 years ago
5 0

Answer:  The correct option is

(A) x < 3.

Step-by-step explanation:  Given that one-third of a number is greater than five less than twice the number.

We are to select the inequality that is TRUE.

Let the required number be represented by x.

Then, according to the given information,we have

\dfrac{1}{3}x>2x-5\\\\\\\Rightarrow x>3(2x-5)\\\\\Rightarrow x>6x-15\\\\\Rightarrow x-6x>-15\\\\\Rightarrow -5x>-15\\\\\Rightarrow 5x-b~~~\Rightarrow a

Thus, the true statement is x < 3.

Option (A) is CORRECT.

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kramer
The answer is d, hope this helps
8 0
2 years ago
Read 2 more answers
5^(-x)+7=2x+4 This was on plato
Setler79 [48]

Answer:

Below

I hope its not too complicated

x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

Step-by-step explanation:

5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}

Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}

\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x

\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

3 0
3 years ago
Write the y-intercept of the graph of -6x + y = 8.
Contact [7]

Answer:

8

Step-by-step explanation:

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What monthly payment for a car lease is $300 for 24 months. The down payment is 1000. The residual value is $9000. What is the t
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Someone please explain this to me.
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Answer:

A is the answer

Step-by-step explanation:

Becuase if it has the same radius and the same height. then they will both be equal.

8 0
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