Given: y varies directly as x squared and inversely as z cubed. If y = 12 when x = 4 and z = 2, find x when y = 1.728 and z = 5.
1 answer:
Answer:
a
Step-by-step explanation:
given y varies directly as x² and inversely as z³ then the equation relating them is
y = ← k is the constant of variation
to find k use the condition y = 12 when x = 4 and z = 2 , then
12 = =
( multiply both sides by 8 )
96 = 16k ( divide both sides by 16 )
6 = k
y = ← equation of variation
when y = 1.728 and z = 5 , then
1.728 = =
( multiply both sides by 125 )
216 = 6x² ( divide both sides by 6 )
36 = x² ( take square root of both sides )
= x , that is
x = 6
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for
the center is (h,k) and the radius is r
and the distance formula is
distance between
r=radius
D=distance form (8,4) to center
if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle
so
the radius is
center is (-2,3)
find distance between (8,4) and (-2,3)
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(8,4) is outside the circle