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2 years ago

13

Drag each tile to the correct box.

1 answer:

devlian [24]2 years ago

4 0

Tax be t

Measure according to blue boxes allignment

#1

t-5/100-24
t-5/76

#2

t-5/100-12
t-5/88

#3

t-3/100-22
t-3/78

#4

t-4/100-24
t-4/76

#5

t-3/100-35
t-3/65.

Remember the rule

Lesser the denominator higher the numerator= Greater value .

So

The order is

2<1<4<5<3

You might be interested in

Karen notices that segment BC and segment EF are congruent in the image below:

LenaWriter [7]

Answer:

Givens:

$A(-2;2) \ B(-2;4) \ C(0;3) \ D(2;1) \ E(2;3) \ F(0;2)$
$BC \cong EF$
$\angle C \cong \angle F$

Using this information we could recur to SAS postulate to demonstrate the congruence of this pair of triangles. We already have one side and one angle congruent, we just need to demonstrate that $AC \cong DF$ , that will prove the complete congruence.

So, based on the given coordinates, we're able to calculate the length of each side and find if they are the same. We use this formula:

$d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\d_{AC} =\sqrt{(0-(-2))^{2}+(3-2)^{2}}=\sqrt{4+1}=\sqrt{5}\\\\\d_{DF} =\sqrt{(0-2)^{2}+(2-1)^{2}}=\sqrt{4+1}=\sqrt{5}$

Therefore, $AC \cong DF$ , because they have the same length.

Now, based on these congruences:

$BC \cong EF$
$\angle C \cong \angle F$
$AC \cong DF$

We demonstrate by the Side-Angle-Side (SAS) postulate that ΔABC ≅ ΔDEF.

6 0

3 years ago

Find x in this 45°-45°-90° triangle.<br><br><br><br> x =

Bezzdna [24]

Answer: 6 sqrt2

Step-by-step explanation:

Sqrt = square root shorthand.

In a 45-45-90, the legs can be represented as x and the hypotenuse as x root2.

12 = x (sqrt2)

12/sqrt2 = x

Let’s rationalize this by putting the square root on top:

12sqrt2 / 2

Simplify:

6sqrt2

6 0

3 years ago

11. Two cyclists start biking from a trail’s start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 h

Margarita [4]

Answer:

<em>4.5 hours</em>

Step-by-step explanation:

distance = velocity × time

8 0

3 years ago

5m + 2 = 47<br> What is the value of m

Volgvan

The value of m is 9. See if you multiply 9 by 5 you get 45 and add two to get 47.

5 0

4 years ago

Read 2 more answers

If S_1=1,S_2=8 and S_n=S_n-1+2S_n-2 whenever n≥2. Show that S_n=3⋅2n−1+2(−1)n for all n≥1.

Snezhnost [94]

You can try to show this by induction:

• According to the given closed form, we have $S_1=3\times2^{1-1}+2(-1)^1=3-2=1$ , which agrees with the initial value <em>S</em>₁ = 1.

• Assume the closed form is correct for all <em>n</em> up to <em>n</em> = <em>k</em>. In particular, we assume

$S_{k-1}=3\times2^{(k-1)-1}+2(-1)^{k-1}=3\times2^{k-2}+2(-1)^{k-1}$

and

$S_k=3\times2^{k-1}+2(-1)^k$

We want to then use this assumption to show the closed form is correct for <em>n</em> = <em>k</em> + 1, or

$S_{k+1}=3\times2^{(k+1)-1}+2(-1)^{k+1}=3\times2^k+2(-1)^{k+1}$

From the given recurrence, we know

$S_{k+1}=S_k+2S_{k-1}$

so that

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 2\left(3\times2^{k-2}+2(-1)^{k-1}\right)$

$S_{k+1}=3\times2^{k-1}+2(-1)^k + 3\times2^{k-1}+4(-1)^{k-1}$

$S_{k+1}=2\times3\times2^{k-1}+(-1)^k\left(2+4(-1)^{-1}\right)$

$S_{k+1}=3\times2^k-2(-1)^k$

$S_{k+1}=3\times2^k+2(-1)(-1)^k$

$\boxed{S_{k+1}=3\times2^k+2(-1)^{k+1}}$

which is what we needed. QED

6 0

3 years ago