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3 years ago

Solve for p. P+9/5=r

Mathematics

1 answer:

alex41 [277]3 years ago

8 0

Hi the answer to your question is p=r-9/5 i hope this helps.

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A locker combination has four nonzero digits. If no digit can be repeated and the first three digits are 1-2-3, what is the prob

Elis [28]

The probability that the fourth digit is 4 is 1/6.

<h3>What is the probability?</h3>

Probability is used to calculate the odds that a random event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

Probability the number is 4 = 1 / possible numbers

Possible numbers = 4, 5, 6, 7, 8, 9,

= 1/6

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

6 0

2 years ago

let a(x) be the amount of money remaining on hilarys gift card after purchasing x apps on her phone since a(12) = ??? , hilary w

mezya [45]

Answer:

Step-by-step explanation:

Given ⇒⇒⇒ a(x)=50-1.25x

a(x) be the amount of money remaining on Hillary's gift card.

x number of apps purchased on her phone

∴ a(12) = 50 - 1.25 * 12 = 35

Which mean : She have amount of total money = 50

she purchased 12 apps costs 12 *1.25 = 15 . So , she spent 15

The remaining on Hillary's gift card = 50 - 15 = 35

The correct answer is :

a(12) =35 .

This means that purchasing 12 apps , Hillary has $35 left

7 0

3 years ago

D.sqrt(2+x^/2)<br> Solve this question please

lidiya [134]

Answer:

Option a.

Step-by-step explanation:

By looking at the options, we can assume that the function y(x) is something like:

$y = \sqrt{4 + a*x^2}$

$y' = (1/2)*\frac{1}{\sqrt{4 + a*x^2} }*(2*a*x) = \frac{a*x}{\sqrt{4 + a*x^2} }$

such that, y(0) = √4 = 2, as expected.

Now, we want to have:

$y' = \frac{x*y}{2 + x^2}$

replacing y' and y we get:

$\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}$

Now we can try to solve this for "a".

$\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}$

If we multiply both sides by y(x), we get:

$\frac{a*x}{\sqrt{4 + a*x^2} }*\sqrt{4 + a*x^2} = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}*\sqrt{4 + a*x^2}$

$a*x = \frac{x*(4 + a*x^2)}{2 + x^2}$

We can remove the x factor in both numerators if we divide both sides by x, so we get:

$a = \frac{4 + a*x^2}{2 + x^2}$

Now we just need to isolate "a"

$a*(2 + x^2) = 4 + a*x^2$

$2*a + a*x^2 = 4 + a*x^2$

Now we can subtract a*x^2 in both sides to get:

$2*a = 4\\a = 4/2 = 2$

Then the solution is:

$y = \sqrt{4 + 2*x^2}$

The correct option is option a.

7 0

3 years ago

The pair of points (-4, y) and (5, 7) lie on a line with slope 1/3 What is the value of y? You must show all of your work to rec

Svetradugi [14.3K]

Answer:

Go back to connections accademy

Step-by-step explanation:

5 0

3 years ago

Is the expression (3^3)-2

Ivan

Answer:

Step-by-step explanation:

(3^3)-2=25

step by step

(3^3)=3^3

=3^3-2

=3^3=27

=27-2

so if we subtract the #: 27-2

The answer will be 25

6 0

2 years ago