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Arisa [49]
2 years ago
14

If y=3x+5 and z=x^2+2x-5, what is yz?

Mathematics
1 answer:
Hitman42 [59]2 years ago
6 0
<h3>Answer:  3x^3 + 11x^2 - 5x - 25</h3>

Work Shown:

yz = y(x^2+2x-5)

yz = y(x^2) + y(2x) + y(-5)

yz = x^2( y ) + 2x( y ) - 5( y )

yz = x^2( 3x+5 ) + 2x( 3x+5 ) - 5( 3x+5 )

yz = x^2*3x + x^2*5 + 2x*3x + 2x*5 - 5*3x - 5*5

yz = 3x^3 + 5x^2 + 6x^2 + 10x - 15x - 25

yz = 3x^3 + 11x^2 - 5x - 25

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area of 3rd rectangle

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Next add all areas together to get the total surface area

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= 418 sq. ft + 308 sq. ft. + 286 sq. ft. + 2(91 sq. ft)

=418 + 308 + 286 + 182

= 1,194 sq. ft.

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