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3 years ago

Identify A, B, and C in the equation x - 3y + 4 = 0.

Mathematics

1 answer:

daser333 [38]3 years ago

5 0

Option D:

A = 1, B = –3 and C = 4.

Solution:

Given equation is x – 3y + 4 =0.

General equation of a line format:

Ax + By + C = 0

To identify A, B and C in the given equation:

x – 3y + 4 =0 is a equation of a line which is in the form of Ax + By + C = 0.

That is,

The coefficient of x is A ⇒ A = 1

The coefficient of y is B ⇒ B = –3

The constant term is C ⇒ C = 4

A = 1, B = –3 and C = 4.

Hence Option D is the correct answer.

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the cylinder has radius 4√3 and hight h. the total surface area of the cylinder is 56π√6. find the exact value of h giving the a

Arte-miy333 [17]

The area of the cylinder is a function of its height (h) and radius, ( $\mathbf{4\sqrt 3}$ )

The exact value of h is: $\mathbf{7\sqrt 2- 4\sqrt 3}$

The given parameters are:

$\mathbf{Area =56\pi\sqrt 6}$

$\mathbf{r=4\sqrt 3}$

The surface area of a cylinder is calculated as:

$\mathbf{Area = 2\pi rh + 2\pi r^2}$

Substitute values for Area

$\mathbf{56\pi\sqrt 6= 2\pi rh + 2\pi r^2}$

Divide through by pi

$\mathbf{56\sqrt 6= 2 rh + 2r^2}$

Substitute value for r

$\mathbf{56\sqrt 6= 2 (4\sqrt 3)h + 2(4\sqrt 3)^2}$

$\mathbf{56\sqrt 6= 8h\sqrt 3 + 2\times 48}$

$\mathbf{56\sqrt 6= 8h\sqrt 3 + 96}$

Collect like terms

$\mathbf{8h\sqrt 3 = 56\sqrt 6- 96}$

Make h the subject

$\mathbf{h = \frac{56\sqrt 6}{8\sqrt 3}- \frac{96}{8\sqrt 3}}$

$\mathbf{h = 7\sqrt 2- \frac{12}{\sqrt 3}}$

Rationalize

$\mathbf{h = 7\sqrt 2- \frac{12\sqrt 3}{3}}$

$\mathbf{h = 7\sqrt 2- 4\sqrt 3}$

Hence, the exact value of h is: $\mathbf{7\sqrt 2- 4\sqrt 3}$

Read more about surface areas t:

brainly.com/question/25131428

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2 years ago

Lines AB and BC intersect at point B. Ray BD bisects angle ABC. (4x-24) B (x+6) What is the value of x?

Verizon [17]

If line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23

The line AB and BC are intersecting at point B.

Ray BD bisect the angle ABC

∠ABD = x+8 degrees

∠ABD=∠DBC = x+8

Because the ray BD bisect the ∠ABC, so ∠ABD and ∠DBC will be equal

∠ABD+∠DBC= 4x-30 degrees

Because both are vertically opposite angles

Substitute the values in the equation

x+8 + x+8 = 4x-30

2x+16 = 4x-30

2x-4x = -30-16

-2x = -46

x = 23

Hence, if line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23

The complete question is

Line AB and BC are intersecting at point B and ray BD bisect the angle ABC. What is the value of x?

Learn more about angle here

brainly.com/question/28451077

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4 0

11 months ago

Can someone help me with 11 A and B?

Elan Coil [88]

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2 years ago

Solve the equation |x-3| -10=-5

Deffense [45]

Answer:

x=8 x=-2

Step-by-step explanation:

|x-3| -10=-5

Add 10 to each side

|x-3| -10+10=-5+10

|x-3| =5

Now separate into two equations , one positive and one negative

x-3 = 5 x-3 = -5

Add 3 to each side

x-3+3 = 5+3 x-3+3 = -5 +3

x=8 x=-2

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2 years ago

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yarga [219]

400 m in 8 hours
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3 years ago