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Agata [3.3K]
2 years ago
7

Graph a triangle (ABC) and reflect it over the x-axis to create triangle A'B'C. Describe the transformation using words. Make su

re you refer
to the characteristics and the coordinates. Draw a line segment from point A to the reflecting line, and then draw a line segment from point
A' to the reflecting line. What do you notice about the two line segments you drew? Do you think you would see the same characteristic if
you drew the line segment connecting B with the reflecting line and then B' with the reflecting line? How do you know?
Mathematics
1 answer:
11Alexandr11 [23.1K]2 years ago
4 0

Following the image of the reflection and the lines drawn, it is clear that the two lines are parallels but NOT equal in length.

<h3>Is it possible to see the same characteristic if one drew the line segment connecting B with the reflecting line and then B' with the reflecting line?</h3>

After drawing the reflecting line, it so happens that in this case the reflecting line fall exactly on the x-axis hence, it does not share the same characteristics.

It is key to recall that a flip is a term used in geometry to describe a reflection. A mirror image of a shape is called a reflection. The line of reflection is a line along which an image reflects.

Learn more about reflection at:
brainly.com/question/26642069
#SPJ1

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mojhsa [17]

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6 0
3 years ago
Andre wants to make a scaled copy of jada drawing so the side that corresponds to 4 units in jada polygon is 8 units of his scal
Contact [7]

Answer:

No she should add extra lengths

Step-by-step explanation:

The difference between scaled copy  and jada drawing is that it is in the ratio

8:4

2:1

that is the scaled copy is twice as large as the jada drawing itself.

So every dimension is doubled or made twice as large as the initial measurement. Andre should not add 4 units to all sides instead the drawing is made twice as large . It will serve the same purpose of enlarging the drawing while maintaining its shape. If extra mesurements are added the drawing will be changed.

3 0
3 years ago
How many lines can you draw using 3 non-collinear points A, B and C on a plane?​
patriot [66]

Answer:3 lines could be used

Step-by-step explanation:

You need 2 points to draw a line. The order doesn't really matter. Line AB is the same as line BA. The problem is to select 2 points out of 3 to draw different lines. If we do the same to the others, we get the following pairs of points to draw lines.

AB , AC

BA , BC

CA , CB

which is only 3 lines

4 0
1 year ago
Given: MNOK is a trapezoid, MN=OK, m∠M=60°, NK ⊥ MN , MK=16cm Find: The midsegment of MNOK. Need help now will give 15 points
Anastaziya [24]

Answer:  24 unit

Step-by-step explanation:

Here,  MNOK is a trapezoid, MN=OK, m∠M=60°, NK ⊥ MN , MK=16cm

Since, a mid segment is the line segment which joins the mid points of the equal sides of the isosceles trapezoid.

Let LO is the mid segment of trapezoid  MNOK

Where, Let J is the intersection point of KN and LO.

Therefore, LO= LJ+JO --------(1)

And, KL=LO , MO=ON

Since, In triangle KLJ,

∠LKJ=90° ( given),  ∠KLJ=60° ( because, LO║ON and it is given m∠M=60°)

Thus, ∠KJL=30°

Therefore, sin 30°=LK/LJ=8/LJ ( Because ΔMKN is a isoceleus triangle where ∠MKN=∠MNK=30°⇒KM=MN)

⇒LJ=8×2=16

Now, In ΔNOJ,

∠ONJ=∠OJN=30°

Therefore, ON=OJ ( by the property of isosceles triangle)

⇒OJ=8

Thus, By putting these values in equation 1) we get,

LO=16+8=24 cm



7 0
4 years ago
4/2n+5/3c=1<br> Solve for c.<br><br> -Multiply both sides by (blank) to clear fractions.
blsea [12.9K]

Answer:

We conclude that:

c=-\frac{5n}{3\left(-n+2\right)};\quad \:n\ne \:2

Step-by-step explanation:

Given the expression

\frac{4}{2n}+\frac{5}{3c}=1

<u>Let us solve for 'c'</u>

\frac{4}{2n}+\frac{5}{3c}=1

Least Common Multiplier of 2n, 3c:   6nc

Now multiply both sides by LCM = 6nc

\frac{4}{2n}\cdot \:6nc+\frac{5}{3c}\cdot \:6nc=1\cdot \:6nc

Simplify

12c+10n=6nc

Subtract 10n from both sides

12c+10n-10n=6nc-10n

Simplify

12c=6nc-10n

Subtract 6nc from both sides

12c-6nc=6nc-10n-6nc

Simplify

12c-6nc=-10n

Factor 12c - 6nc = 6c(2-n)

6c\left(2-n\right)=-10n

Divide both sides by 6(2-n);  n≠2

\frac{6c\left(2-n\right)}{6\left(2-n\right)}=\frac{-10n}{6\left(2-n\right)};\quad \:n\ne \:2

simplify

c=-\frac{5n}{3\left(-n+2\right)};\quad \:n\ne \:2

Therefore, we conclude that:

c=-\frac{5n}{3\left(-n+2\right)};\quad \:n\ne \:2

4 0
3 years ago
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