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Agata [3.3K]
1 year ago
7

Graph a triangle (ABC) and reflect it over the x-axis to create triangle A'B'C. Describe the transformation using words. Make su

re you refer
to the characteristics and the coordinates. Draw a line segment from point A to the reflecting line, and then draw a line segment from point
A' to the reflecting line. What do you notice about the two line segments you drew? Do you think you would see the same characteristic if
you drew the line segment connecting B with the reflecting line and then B' with the reflecting line? How do you know?
Mathematics
1 answer:
11Alexandr11 [23.1K]1 year ago
4 0

Following the image of the reflection and the lines drawn, it is clear that the two lines are parallels but NOT equal in length.

<h3>Is it possible to see the same characteristic if one drew the line segment connecting B with the reflecting line and then B' with the reflecting line?</h3>

After drawing the reflecting line, it so happens that in this case the reflecting line fall exactly on the x-axis hence, it does not share the same characteristics.

It is key to recall that a flip is a term used in geometry to describe a reflection. A mirror image of a shape is called a reflection. The line of reflection is a line along which an image reflects.

Learn more about reflection at:
brainly.com/question/26642069
#SPJ1

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EleoNora [17]

Answer:

15 \sqrt[3]{2}

Step-by-step explanation:

{(27 \times 250)}^{ \frac{1}{3} }  =  {(27 \times 125 \times 2)}^{ \frac{1}{3} }  \\  =  {27}^{ \frac{1}{3} }  \times  {125}^{ \frac{1}{3} }  \times  {2}^{ \frac{1}{3} }  \\  =  \sqrt[ 3]{27}  \times  \sqrt[3]{125}  \times  \sqrt[3]{2}  \\  =  \sqrt[3]{ {3}^{3} }  \times  \sqrt[3]{ {5}^{3} }  \times  \sqrt[3]{2}  \\  = 3 \times 5 \times  \sqrt[3]{2}  \\  = 15 \sqrt[3]{2}

4 0
3 years ago
Which equation has the same solutions as 4x + x - 5 = 0 ?
Lyrx [107]
5x-5=0
You simplify the left side
4 0
1 year ago
Read 2 more answers
Can someone help me with this? Right answer gets brainliest!! :)
Sedbober [7]

I have 2 answers in mind

Answer #1:

\frac{y}{z}

Step-by-step explanation:

quotient means the answer to 2 things being divided so the quotient of y and z would be \frac{y}{z} because there is no numerical value.

Answer #2:

1

Step-by-step explanation:

Usually, when a letter is left by itself in an equation it usually has an invisible one in front of it. so when dividing y by z it would equal 1/1 which is equal to one.

Hope this helps :)

6 0
3 years ago
Given a rectangle with length of (2x+9)cm and width of (3x+1)cm.Two squares, each with sides x cm is removed from the rectangle.
il63 [147K]

Answer: The length is 13cm and the width is 7cm

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = W*L

In this case we have:

L = (2*x + 9) cm

W=(3*x + 1) cm

Then the area of the rectangle is:

A = (2*x + 9)*(3*x + 1) cm^2

A = (6*x^2 + 2*x + 27*x + 9) cm^2

A = (6*x^2 + 29*x + 9) cm^2

now we remove two squares with sides of x cm

The area of each one of these squares is (x cm)*(x cm)  = x^2 cm^2

Then the area of the figure will be:

area = (6*x^2 + 29*x + 9) cm^2 - (2*x^2 ) cm^2

area = (4*x^2 + 29*x + 9) cm^2

Now we know that the area of this shape is 83 cm^2, then we need to solve:

83 cm^2 = (4*x^2 + 29*x + 9) cm^2

0 =  (4*x^2 + 29*x + 9) cm^2 - 83 cm^2

0 = (4*x^2 + 29*x - 74) cm^2

Then we need to solve:

0 = 4*x^2 + 29*x - 74

Here we can use Bhaskara's equation, the solutions of this equation are given by:

x = \frac{-29 \pm \sqrt{29^2 - 4*4*(-74)}  }{2*4} = \frac{-29 \pm 45}{8}

Then the two solutions are:

x = (-29 - 45)/8 = -9.25  (for how the length and width are defined, we can not have x as a negative number, then this solution can be discarded).

The other solution is:

x = (-29 + 45)/8 = 2

x = 2

Then the length and width of the rectangle are:

Length = (2*2 + 9)cm = 13 cm

Width = (3*2 + 1)cm = 7cm

4 0
2 years ago
Use a number line to solve 5+7
Neporo4naja [7]
To start off, 5+7=12, so we already know how the number line will be laid out. We will have Point A on 5, and count up 7 units, plotting Point B on 12.
6 0
2 years ago
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