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2 years ago

13

What -4 times 7 on a number line

1 answer:

Julli [10]2 years ago

6 0

Answer:

-28

Step-by-step explanation:

-4(7)=-28

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A school production sold 480 tickets, including 325 tickets to adults. The rest were sold to

Tju [1.3M]

I believe it would be 96/65

3 0

2 years ago

Let m=4 and n=36. What is the value of m+.9?

Anna11 [10]

Answer:
4.9

Explanation:
We are given m = 4 and n = 36 and the expression m + .9.

Replace m with the given value:
4 + .9

Add them together:
4.9

3 0

2 years ago

Find the value of b+7 when b=19

Leona [35]

use the substitution method

b+7

19+7

Answer: 26

7 0

3 years ago

Read 2 more answers

Determine the open t-intervals on which the curve is concave downward or concave upward. (Enter your answer using interval notat

Rashid [163]

Solution :

We have been given a parametric curve :

x = sin t , y = cos t , 0 < t < π

In order to determine concavity of the given parametric curve, we need to evaluate its second derivative first.

Therefore,

$\frac{dx}{dt} = \cos t, \ \frac{dy}{dt}= - \sin t$

$\therefore \frac{dy}{dx}= \frac{- \sin t}{\cos t}$

$=- \tan t$

Taking double derivatives of the above equation:

$\frac{d^2y}{dx^2}= - \frac{d}{dx}(\tan t)$

$= - \sec^2 t \frac{dt}{dx}$

$= - \sec^2 t \left(\frac{1}{\cos t}\right)$

$= - \sec^3 t$

For the concave up, we have

$\frac{d^2y}{dx^2} > 0$

$\Rightarrow - \sec^3 t > 0$

∴ $t \ \epsilon \left( \frac{\pi }{2}, \pi \right)$

For the concave down, we have

$\frac{d^2y}{dx^2} < 0$

$\Rightarrow - \sec^3 t < 0$

$t \ \epsilon \left( 0,\frac{\pi }{2} \right)$

8 0

3 years ago

A 2-column table has 5 rows. The first column is labeled x with entries negative 2, negative 1, 0, 1, 2. The second column is la

andriy [413]

Answer:

Initial value is $\frac{1}{2}$ .

Step-by-step explanation:

Let us assume that the exponential function is $f(x) = a(b)^{x}$ ...... (1)

Now, the point $(0,\frac{1}{2})$ will satisfy the above equation.

Now, this point on the graph of the exponential function will be sufficient to find the initial value of the function (1) i.e. a.

Now, putting the value x = 0 and $y = \frac{1}{2}$ in the equation (1) we get, $f(x) = a(b)^{x}$

⇒ $\frac{1}{2} = a(b)^{0} = a$

⇒ $a = \frac{1}{2}$ (Answer)

10 0

2 years ago

Read 2 more answers