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kherson [118]
2 years ago
6

A support wire reaches from the top of a pole to a clamp on the ground. The pole is

Mathematics
1 answer:
Burka [1]2 years ago
6 0

The length of the support wire on the pole is 27 feet

<h3>How to determine the length of the support?</h3>

The given parameters are:

  • Distance from the base, b = 10 feet
  • Angle with the ground, x = 68 degrees

The length (L) of the support wire is then calculated using the following cosine function

cos(x) = b/L

This gives

cos(68) = 10/L

Make L the subject

L = 10/cos(68)

Evaluate

L = 27

Hence, the length of the support wire is 27 feet

Read more about triangles at:

brainly.com/question/1675117

#SPJ1

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Answer:

Step-by-step explanation:

the current ages:

father= 32 yrs old

son=5 yrs old

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4(5+x) = 32+x

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3x =12

x = 12/3

x = 4 years

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Vector V is in standard position and makes an angle of 50° with the positive x-axis. Its magnitude is 18. Write V in component f
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Answer:

11.57 units east, 13.79 units upwards

11.57i + 13.79j

Step-by-step explanation:

V = 18 units at an angle of 50° to the positive x-axis

In component Form, this is how each component is calculated

a = 18cos50° = 11.57 units east

b = 18sin50° = 13.79 units upwards

check if your answer is correct

\sqrt{11.57^{2} +13.79^{2} } = 18.0

In vector component form ai + bj = 11.57i + 13.79j

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Suppose the mean SAT verbal score is 525 with a standard deviation of 100, while the mean SAT math score is 575 with a standard
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Answer:

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

Step-by-step explanation:

Normal variables

Normal variables have mean \mu and standard deviation \sigma

When we add normal variables, the combined mean is the sum of both means, and the standard deviation is the square root of the sum of both variances. The distribution is still normal.

In this question:

Verbal: \mu_{V} = 525, \sigma_{V} = 100.

Math: \mu_{M} = 575, \sigma_{M} = 100

Combined:

\mu = \mu_{V} + \mu_{M} = 525 + 575 = 1100

\sigma = \sqrt{\sigma_{V}^{2}+\sigma_{M}^{2}} = \sqrt{100^2 + 100^2} = 141

The mean of the combined math and verbal scores is 1100, while the standard deviation is 141.

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