Ask question

Ask question

All categories

2 years ago

15

I would like to know how to solve this problem.

1 answer:

julsineya [31]2 years ago

7 0

Answer:

option 1 is the answers for the question

Step-by-step explanation:

please mark me as brainlest

You might be interested in

Please help me asap i need it

TiliK225 [7]

Answer:

j) y=2/5x-1

Step-by-step explanation:

you can use desmos graphing calculator to help you on questions like these, all you gotta do is input each answer and you get a visual representation of what they look like. Hope this helps!

6 0

3 years ago

Read 2 more answers

Lee drove 420 miles and used 15 gallons of gasoline. How many miles did Lee’s car travel per gallon of gasoline?

olasank [31]

Answer:

28 miles per gallon

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the median for 8, 11, 6, 14, x, 13, and 11

Rainbow [258]

Median = 11. Sorry if wrong

If right, pls mark brainliest i wanna get virtuoso.
Have a great day

4 0

3 years ago

A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What

vladimir2022 [97]

Answer:

The perimeter of the triangle is $12\ units$

Step-by-step explanation:

Let

$A(-3,1),B(1,1),C(1,-2)$

we know that

The perimeter of triangle is equal to

$P=AB+BC+AC$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

step 1

Find the distance AB

$A(-3,1),B(1,1)$

substitute in the formula

$AB=\sqrt{(1-1)^{2}+(1+3)^{2}}$

$AB=\sqrt{(0)^{2}+(4)^{2}}$

$AB=4\ units$

step 2

Find the distance BC

$B(1,1),C(1,-2)$

substitute in the formula

$BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}$

$BC=\sqrt{(-3)^{2}+(0)^{2}}$

$BC=3\ units$

step 3

Find the distance AC

$A(-3,1),C(1,-2)$

substitute in the formula

$AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}$

$AC=\sqrt{(-3)^{2}+(4)^{2}}$

$AC=5\ units$

step 4

Find the perimeter

$P=AB+BC+AC$

substitute the values

$P=4+3+5=12\ units$

6 0

3 years ago

CON PROCESOS POR FAVOR

labwork [276]

Answer:

$\dfrac{149}{40}$

$\dfrac{38}{15}$

Step-by-step explanation:

$(\dfrac{7}{8} + \dfrac{4}{5}) - (\dfrac{9}{20} + \dfrac{-5}{2}) =$

$= (\dfrac{7}{8} \times \dfrac{5}{5} + \dfrac{4}{5} \times \dfrac{8}{8}) - (\dfrac{9}{20} + \dfrac{-5}{2} \times \dfrac{10}{10})$

$= (\dfrac{35}{40} + \dfrac{32}{40}) - (\dfrac{9}{20} + \dfrac{-50}{20})$

$= \dfrac{67}{40} - (-\dfrac{41}{20})$

$= \dfrac{67}{40} + \dfrac{41}{20} \times \dfrac{2}{2}$

$= \dfrac{67}{40} + \dfrac{82}{40}$

$= \dfrac{149}{40}$

$(-\dfrac{6}{4} + \dfrac{3}{2}) + (\dfrac{6}{5} + \dfrac{4}{3}) =$

$= (-\dfrac{3}{2} + \dfrac{3}{2})+ (\dfrac{6}{5} \times \dfrac{3}{3} + \dfrac{4}{3} \times \dfrac{5}{5})$

$= 0 + \dfrac{18}{15} + \dfrac{20}{15}$

$= \dfrac{38}{15}$

4 0

2 years ago