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Nuetrik [128]
3 years ago
10

The graph of a system of inequalities is shown.

Mathematics
2 answers:
dangina [55]3 years ago
8 0

Answer:

The system is

x+2y \leq -8

y> 2x

Step-by-step explanation:

Part 1

<u><em>Find the equation of the first inequality</em></u>

we know that

The first line is a solid line with negative slope passing through the points (-6,-1) and (0,-4)

The slope is equal to

m=(-4+1)/(0+6)\\m=-0.5

The equation of the solid line in slope intercept form is

y=-0.5x-4

Everything below the line is shaded

so

The inequality is

y \leq -0.5x-4

Convert to standard form

Adds 0.5x both sides

0.5x+y \leq -4

Multiply by 2 both sides

x+2y \leq -8 -----> First inequality

Part 2

<u><em>Find the equation of the second inequality</em></u>

we know that

The second line is a dashed line with positive slope passing through the points (-2,-4) and (0,0)

This line represent a proportional relationship, because the line passes through the origin

The slope is equal to the constant of proportionality

k=(-4)/(-2)=2

The equation of the dashed line is

y=2x

Everything to the left of the line is shade

so

The inequality is

y> 2x -----> Second inequality

see the attached figure to better understand the problem

Anni [7]3 years ago
6 0

Answer:

the correct anwser is A.......

     y > 2x

x + 2y ≤ –8               just took the  unit test

Step-by-step explanation:

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\dfrac{ \dfrac{x+3}{4x^2-16} }{ \dfrac{2x^2+10x+12}{2x-4} }

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Write the divide fraction horizontally:
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= \dfrac{x+3}{4x^2-16} \div \dfrac{2x^2+10x+12}{2x-4}

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Factorise the numerators and denominators when possible:
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= \dfrac{x+3}{4(x+2)(x-2)} \div \dfrac{ 2(x + 3) (x + 2)}{2(x-2)}

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Convert the divide fraction to multiplication fraction
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= \dfrac{x+3}{4(x+2)(x-2)} \times \dfrac{2(x-2)}{2(x+3)(x+2)}

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Cancel the factors
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= \dfrac{1}{4(x+2)} \times \dfrac{1}{(x+2)}

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Combine to single fraction
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= \dfrac{1}{4(x+2)^2}



4 0
3 years ago
For
Dmitry [639]

Answer:

8 in^2.

Step-by-step explanation:

F = P * A

22 = 2.75 * A

A = 22/ 2.75

A = 8 in^2.

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What is the quadratic domain of y=x squared
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domain is the numbes you are allowed to use for x

what I usually do is just find the numbers that aren't allowed in the domain. such numbers are numbers that cause a division by 0 or a squaer root of a negative number

given y=x^2, there are no numbers that you can use for x that will cause a division by 0 or a square root of a negative number


so domain is all real numbers or D={x | -∞<x<∞}

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The answer would be the median is 10 because if u actually take the time and draw it you x everything out and see whats in the middle and you will have 10 dots lolz hope this helped

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