Answer:
Hello!
After reading your question I have come up with the correct way to factor (x-4) and (x-3) together:
x²-7x+12
Step-by-step explanation:
This is my work:
Answer:

Step-by-step explanation:
The motion equations that describe the ball are, respectively:
![x = \left[\left(152\,\frac{ft}{s} \right)\cdot \cos 52^{\circ} \right] \cdot t](https://tex.z-dn.net/?f=x%20%3D%20%5Cleft%5B%5Cleft%28152%5C%2C%5Cfrac%7Bft%7D%7Bs%7D%20%5Cright%29%5Ccdot%20%5Ccos%2052%5E%7B%5Ccirc%7D%20%5Cright%5D%20%5Ccdot%20t)
![y = 4.5\,ft + \left[\left(152\,\frac{ft}{s} \right)\cdot \sin 52^{\circ} \right] \cdot t - \frac{1}{2}\cdot \left(32.174\,\frac{ft}{s^{2}} \right) \cdot t^{2}](https://tex.z-dn.net/?f=y%20%3D%204.5%5C%2Cft%20%2B%20%5Cleft%5B%5Cleft%28152%5C%2C%5Cfrac%7Bft%7D%7Bs%7D%20%5Cright%29%5Ccdot%20%5Csin%2052%5E%7B%5Ccirc%7D%20%5Cright%5D%20%5Ccdot%20t%20-%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Cleft%2832.174%5C%2C%5Cfrac%7Bft%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%20%5Ccdot%20t%5E%7B2%7D)
The time required for the ball to hit the ground is computed from the second equation. That is to say:
![4.5\,ft + \left[\left(152\,\frac{ft}{s} \right)\cdot \sin 52^{\circ} \right] \cdot t - \frac{1}{2}\cdot \left(32.174\,\frac{m}{s^{2}} \right) \cdot t^{2} = 0](https://tex.z-dn.net/?f=4.5%5C%2Cft%20%2B%20%5Cleft%5B%5Cleft%28152%5C%2C%5Cfrac%7Bft%7D%7Bs%7D%20%5Cright%29%5Ccdot%20%5Csin%2052%5E%7B%5Ccirc%7D%20%5Cright%5D%20%5Ccdot%20t%20-%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Cleft%2832.174%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%20%5Ccdot%20t%5E%7B2%7D%20%3D%200)
Given that formula is a second-order polynomial, the roots of the equation are described below:
and 
Just the first root offers a realistic solution. Then,
.
Answer:
22900
Step-by-step explanation:
multiply 350 by 6 and get 2100
subtract 2100 from 25k and get 22900
Answer:
Step-by-step explanation:
Note that there are two scale models with each of ratio of 1/2 and 1/16 respectively.
For the first model, the dimension will be as follows:
Length/2 by width/2
94/2 by 50/2 = 47 feet by 25 feet.
For the second model, the dimension will be as follows:
Length/16 by width/16
The dimensions of the second model is 94/16 by 50/16 = 5.875 feet by 3.125 feet.
Since we are to solve for the area of the smallest scale model which is
5.875 feet by 3.125 feet.
Hence, area (A) = L× W
=5.875 × 3.125 feet.
= 18.359ft^2