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Lapatulllka [165]
4 years ago
15

Write an exponential equation in the form y = ab^x whose graph passes through points (4, 8) and (6, 32).

Mathematics
1 answer:
luda_lava [24]4 years ago
5 0

Answer:

(1,4),(2,12)

----------

The form is y = ab^x

12 = ab^2

4 = ab^1

------------

Divide the 1st by the 2nd to get:

3 = b

--------

Substitute that into the 2nd equation to solve for "a":

4 = a*3^1

a=(4/3)

-------------

EQUATION:

y = (4/3)*2^x

==================

Step-by-step explanation:

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The equation of the circle  <em>(x + 5 )² + ( y + 10 )² = (4)²</em>

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Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given circle equation is x² + y² +10 x + 20 y +109 =0

                                     x² +10 x +  y² + 20 y +109 =0

  x² +2 (5) (x)+(5)² -(5)²+ y² +2(10) y + (10)²-(10)² +109 =0

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<em>(x + 5 )² + ( y + 10 )² - 25 - 100 + 109 = 0</em>

<em>(x + 5 )² + ( y + 10 )² - 16 = 0</em>

<em>(x + 5 )² + ( y + 10 )² = 16</em>

(x + 5 )² + ( y + 10 )² = (4)²

The standard equation of the circle  ( x - h )² + ( y -k)² = r²

<em> Center of the circle ( h, k) = ( -5 , -10)</em>

<em>Radius of the circle     ' r' = 4</em>

<u><em>Conclusion</em></u><em>:-</em>

The equation of the circle  <em>(x + 5 )² + ( y + 10 )² = (4)²</em>

<em>Center of the circle ( h, k) = ( -5 , -10)</em>

<em>Radius of the circle     ' r' = 4</em>

<em></em>

3 0
3 years ago
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