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Lapatulllka [165]
3 years ago
15

Write an exponential equation in the form y = ab^x whose graph passes through points (4, 8) and (6, 32).

Mathematics
1 answer:
luda_lava [24]3 years ago
5 0

Answer:

(1,4),(2,12)

----------

The form is y = ab^x

12 = ab^2

4 = ab^1

------------

Divide the 1st by the 2nd to get:

3 = b

--------

Substitute that into the 2nd equation to solve for "a":

4 = a*3^1

a=(4/3)

-------------

EQUATION:

y = (4/3)*2^x

==================

Step-by-step explanation:

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Answer:   " 6 \frac{5}{6}  ".

Step-by-step explanation:

______________________________________

2 \frac{2}{6} + 4\frac{3}{6}  = 2 + 4 + \frac{2}{6} + \frac{3}{6}  ;

           = 6 + \frac{2}{6} + \frac{3}{6}  ;

______________________________________

   →  \frac{2}{6}+\frac{3}{6} = \frac{(2+3)}{6} = \frac{5}{6} ;

   →  6 +\frac{2}{6}+ \frac{3}{6} = 6 + \frac{(2+3)}{6} = 6 \frac{5}{6}  .

______________________________________

   →  The answer is: " 6 \frac{5}{6}  ".

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8 0
3 years ago
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Answer:


Step-by-step explanation:

xy = k    

where k is the constant of variation.

We can also express the relationship between x and y as:

y =      

where k is the constant of variation.

Since k is constant, we can find k given any point by multiplying the x-coordinate by the y-coordinate. For example, if y varies inversely as x, and x = 5 when y = 2, then the constant of variation is k = xy = 5(2) = 10. Thus, the equation describing this inverse variation is xy = 10 or y = .

Example 1: If y varies inversely as x, and y = 6 when x = , write an equation describing this inverse variation.

k = (6) = 8  

xy = 8 or y =  

Example 2: If y varies inversely as x, and the constant of variation is k = , what is y when x = 10?

xy =  

10y =  

y = × = × =  

k is constant. Thus, given any two points (x1, y1) and (x2, y2) which satisfy the inverse variation, x1y1 = k and x2y2 = k. Consequently, x1y1 = x2y2 for any two points that satisfy the inverse variation.

Example 3: If y varies inversely as x, and y = 10 when x = 6, then what is y when x = 15?

x1y1 = x2y2  

6(10) = 15y  

60 = 15y  

y = 4  

Thus, when x = 6, y = 4.



2nd answer choice


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