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levacccp [35]
2 years ago
13

X2 can be combined with X?

Mathematics
2 answers:
natulia [17]2 years ago
3 0

Answer:

Your first instinct might be to go ahead and add the x terms together, BUT this would be a bad thing to do! You cannot combine the x2 and 2x, because the first term has an exponent (2) and the second one does not have an exponent; therefore, you cannot add them together!

Step-by-step explanation:

tino4ka555 [31]2 years ago
3 0

Answer:

Not sure if you mean multiplying or adding by "combine". But generally the rule of thumb with exponents is when you are adding and they are not like terms, you cannot combine the two terms together. So in other words, they would be left as x²+x. However, when you are multiplying you can add the exponents together. So, it will be like this: x²·x = x³

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What's the most effective method for controlling inventory ? a ) Electronically , by reviewing billing receipts b ) Electronical
mina [271]

Answer:

a ) Electronically , by reviewing billing receipts

Step-by-step explanation:

The main purpose of controlling inventory is to make sure that the optimal amount of products are being kept.

Therefore, option A is correct.

8 0
1 year ago
Birth weights at a local hospital have a Normal distribution with a mean of 110 oz and a standard deviation of 15 oz. The propor
OLga [1]

Answer:

The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 110, \sigma = 0.15

The proportion of infants with birth weights between 125 oz and 140 oz is

This is the pvalue of Z when X = 140 subtracted by the pvalue of Z when X = 125. So

X = 140

Z = \frac{X - \mu}{\sigma}

Z = \frac{140 - 110}{15}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 125

Z = \frac{X - \mu}{\sigma}

Z = \frac{125 - 110}{15}

Z = 1

Z = 1 has a pvalue of 0.8413

0.9772 - 0.8413 = 0.1359

The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.

4 0
3 years ago
A football team gains 7 yards in the first down then gains 2 yards in the second down. Then loses 4 yards in the third yard. Wha
Alinara [238K]

Answer: 5

Step-by-step explanation:

First we should do the first step: 7+2=9, The they lose 4 which then 9-4

which would equal 5

6 0
2 years ago
Read 2 more answers
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vova2212 [387]
The answer is b. 43!!
7 0
3 years ago
$2is what percent of $10
sammy [17]

Answer:

2persent

Step-by-step explanation:

because there are 10 10 in 100

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2 years ago
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