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eimsori [14]
2 years ago
5

Find the interval on which the function is continuous

Mathematics
1 answer:
marin [14]2 years ago
6 0

Answer:The function is continuous at all points except where x=-4. The domain of the function can be given by. (-oo, -4)uu(-4, oo) The given ...

Step-by-step explanation:

How do you find what interval a function is continuous?

Image result for find the interval on which the function is continuous example

A function ƒ is continuous over the open interval (a,b) if and only if it's continuous on every point in (a,b). ƒ is continuous over the closed interval [a,b] if and only if it's continuous on (a,b), the right-sided limit of ƒ at x=a is ƒ(a) and the left-sided limit of ƒ at x=b is ƒ(b)

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I need help badly with this Algebra question, if someone could explain how to solve this It'd really help.
Alex

Answer:

The answer is A, or the top left function.

Step-by-step explanation:

Use the vertical line test. If you can draw a straight, vertical line through the graph, and the function intersects it at 2 or more points, it is NOT a function. Using this logic, only A is the answer.



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3 years ago
The difference of −2d and −3d is equal to the difference of 1/6 and 1/3
sertanlavr [38]

Answer:

  • d = -1/6

Step-by-step explanation:

<u>The difference of −2d and −3d is equal to the difference of 1/6 and 1/3</u>

  • -2d - (-3d) = 1/6 - 1/3
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3 years ago
A right-angled triangle has a hypotenuse
oksian1 [2.3K]

Answer:

P = 108cm

A = 486 cm^2

Step-by-step explanation:

To find the perimeter add up all the side

P = 36+27+ 45 =108 cm

The area is

A = 1/2 bh

A = 1/2( 27)*36

A = 486 cm^2

5 0
3 years ago
Prove that the inequality (a+1)·(a+1)&gt;(a−1)·(a−1) is not true for some values of a.
Effectus [21]

Explanation:

Consider the case a = -1. Then the expression becomes ...

  (-1+1)(-1+1) > (-1-1)(-1-1) . . . . test case

  0·0 > (-2)(-2) . . . . . simplified a bit

  0 > 4 . . . . . . . . NOT TRUE

_____

If we subtract the right side from both sides, the inequality becomes ...

  (a+1)(a+1) -(a-1)(a-1) > 0

  a² +2a +1 -(a² -2a +1) > 0

  4a > 0

  a > 0

The inequality is only true for positive values of "a". For a ≤ 0, the inequality will not be true.

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4 years ago
Which equation describes a nonlinear function of x?
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Answer:the answer is C

Step-by-step explanation:

4 0
3 years ago
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