Question

EGG DROP The physics class is holding an egg drop competition. The formula h= −16t2+h0 can be used to approximate the number of seconds, t, it will take for the eggs to reach height, h, from an initial height of h0 in feet.
Find the time it takes an egg to reach the ground if it is dropped from an initial height of 40 feet. Round to the nearest hundredth, if necessary.

Answer 1

By solving a quadratic equation we will see that the egg will hit the ground after 1.58 seconds.

How long will take the egg to reach the ground?

Here we know that the initial height of the egg is 40ft, so the equation for the height will be:

$h(t) = -16*t^2 + 40$

The egg will hit the ground when h(t) = 0, so we need to solve the quadratic equation:

$h(t) = -16*t^2 + 40 = 0\\\\16t^2 = 40\\\\t^2 = 40/16\\\\t = \sqrt{40/16} = 1.58$

This means that the egg will hit the ground after 1.58 seconds.

If you want to learn more about quadratic equations:

brainly.com/question/1214333

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