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3 years ago

What is conflict resolution?

Physics

1 answer:

andriy [413]3 years ago

3 0

Answer:

B) Settling a dispute or disagreement

Explanation:

A conflict is a disagreement or argument between opposing parties.

A resolution is a solution to a problem.

Knowing both these definitions, the answer choice that makes the most sense would be B) Settling a dispute or disagreement.

Hope this helps!!

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PLEASE HELP ME ASAP!!!!!!!!!

NNADVOKAT [17]

Answer:

letter C. velocity hope this helps

7 0

3 years ago

As a diligent physics student, you carry out physics experiments at every opportunity. At this opportunity, you carry a 1.01 m l

Valentin [98]

Answer:

The strength of the magnetic field is $75.6\ \mu T$ .

Explanation:

Given that,

Length of the rod, L = 1.01 m

Speed with which the rod is moving, v = 3.47 m/s

We need to find the strength of the magnetic field that is perpendicular to both the rod and your direction of motion and that induces an EMF of 0.265 mV across the rod. When the rod is moving with some speed, an emf gets induced and it is given by :

$\epsilon=Blv$

B is magnetic field

$B=\dfrac{\epsilon}{lv}\\\\B=\dfrac{0.265\times 10^{-3}}{1.01\times 3.47}\\\\B=75.6\ \mu T$

So, the strength of the magnetic field is $75.6\ \mu T$ .

6 0

4 years ago

An average person can reach a maximum height of about 60 cm when jumping straight up from a crouched position. During the jump i

Iteru [2.4K]

Answer:

Explanation:

Height attained by body = 50 cm

= .5 m

Initial velocity = u

v² = u² - 2gh

0 = u² - 2gh

u² = 2 x 9.8 x .5

u = 3.13 m /s

During the initial period , the muscle stretches by around 10 cm during which force by ground reacts on the body and gives acceleration to achieve velocity of 3.13 m/s from zero .

v² = u² + 2as

3.13² = 0 + 2 a x .10

a = 49 m/s²

reaction by ground R

Net force

R-mg = ma

R= m ( g +a )

= mg + ma

=W + (W/g) x a

W ( 1 + a / g )

= W ( 1 + 49 / 9.8 )

= 6W

4 0

4 years ago

The spring to launch a pinball in a pinball machine is compressed 25 cm and has a spring constant of 140 N/m.

mote1985 [20]

Answer:

I think it is 5.6. This is my answer

8 0

3 years ago

Sir Percival and his horse are standing still on a field of honor when Sir Rodney, atop his steed gallops by with a constant vel

Ludmilka [50]

Answer:

d. none of these

Explanation:

From the given information:

Let assume that Percival catches Sir Rodney's horse in time "t" after covering a certain distance "s"

Then, using the second equation of motion:

$S = ut + \dfrac{1}{2}at^2$

FOR Percival, we have:

$S = (0\times t ) + \dfrac{1}{2} \times 0.6 \ m/s \times t^2 \\ \\ S = 0.3 \ m/s \times t^2 -- -- (1)$

FOR Sir Rodney;

$S = ut + \dfrac{1}{2}at^2$

$S = (3\times t ) + \dfrac{1}{2} \times 0 \times t^2 \\ \\ S =3t--- (2)$

Equating both equations together; we have:

0.3t² = 3t

0.3t² - 3t = 0

0.3t(t - 10) = 0

If Percival's position at rest = 0

Then; t = 10 s.

8 0

3 years ago