Answer:
variations in great horned owl body size due to food supply can be acted on by natural selection.
Explanation:
Natural selection can help select great horned owl with smaller body size since it's an advantage in a place with smaller available food sources, compared to a bigger body size that will need more food. At first, birds with smaller body survive while those bigger ones die out, and the smaller birds pass on this genes to their offspring.
Answer:
variation in body size due to inherited traits can be acted on by natural selection
Explanation :
Variations in body size in body size due to inherited trait can be acted upon by natural selection by favoring the size that is best suited for the survival of the species. Those with these genes survive and pass it on to their offspring, while those with the unfavorable body size are wiped out.
Answer:
momentum in a body can be calculated using
<em><u>Mome</u></em><em><u>ntum</u></em><em><u>=</u></em><em><u>Mass×</u></em><em><u>V</u></em><em><u>e</u></em><em><u>l</u></em><em><u>o</u></em><em><u>s</u></em><em><u>i</u></em><em><u>t</u></em><em><u>y</u></em><em><u> </u></em>
<em><u>i</u></em><em><u>e(</u></em><em><u>p</u></em><em><u>=</u></em><em><u>m×</u></em><em><u>v</u></em><em><u>)</u></em>
Answer:
a) F₁₂₀ = 1.34 pa A , b) F₂₀ = 0.746 pa A
Explanation:
Part. A
. The definition of pressure is
P = F / A
As the air can approach an ideal gas we can use the ideal gas equation
P V = n R T
Let's write this equation for two temperatures
P₁ V = n R T₁
P₂2 V = n R T₂
P₁ / P₂ = T₁ / T₂
point 1 has a pressure of P₁ = pa and a temperature of (20 + 273) K, point 2 is at (120 + 273) K, we calculate the pressure P₂
P₂ = P₁ T₂ / T₁
P₂ = pa 393/293
P₂ = 1.34 pa
We calculate the strength
P₂ = F₁₂₀ / A
F₁₂₀ = 1.34 pa A
Part B
In this case the data is
Point 1 has a temperature of 393K and an atmospheric pressure (P₁ = pa), point 2 has a temperature of 293K, let's calculate its pressure
P₁ / P₂ = T₁ / T₂
P₂ = P₁ T₂ / T₁
P₂ = pa 293/393
P₂ = 0.746 pa
Let's calculate the force (F20), from this point
F₂₀ / A = 0.746 pa
F₂₀ = 0.746 pa A
Questions in this category that include the words "This graphic shows..."
or some such, frequently fail to include any graphic. When no graphic is
included, it must follow as the night follows the day that no physics is pictured
in the scene. Inertia is a very popular subject, often appearing in scenes
where physics is pictured. Sadly, however, in an environment that is totally
devoid of graphics, projectiles and the inertia they carry are seldom to be found.