The measure of the third angle in the ΔABC is 70 degrees
<h3>Complete question</h3>
In ΔABC, m∠2 = 70 and m∠1 = 40, find the measure of all third angle of ΔABC.
<h3>How to determine the third angle?</h3>
The given parameters are:
m∠2 = 70
m∠1 = 40
The sum of angles in a triangle is:
m∠1 + m∠2 + m∠3 = 180
So, we have:
70 + 40 + m∠3 = 180
Subtract 110 from both sides
m∠3 = 70
Hence, the measure of the third angle in the ΔABC is 70 degrees
Read more about triangles at:
brainly.com/question/1675117
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