Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
D. because you have to get the price of the elastic, and ribbon and then add them together
X+y=14 (*25)
35x+25y=410
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35x+25y=410
25x+25y=350
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10x=60
x=6
⓵
-4ỿ = 8
Simplify the left side in order to isolate the ỿ!
-4ỿ = 8
+4 +4
Ỿ = 12
⓶
× + 3y - 3z = -26
Simplify the left side in order to isolate the ×, ỿ and z!
× + 3y - 3z = -26
÷3 ÷3
× + ỿ - 3z = -8,66 periodic
÷-3 ÷-3
× + ỿ + z = 2,88 periodic
⓷
2× - 5ỿ + z = 19
Simplify the left side in order to isolate the ×, ỿ and z!
2× - 5ỿ + z = 19
÷2 ÷2
× - 5ỿ + z = 9,5
÷-5 ÷-5
× + ỿ + z = -1,9
Answer:
add them
Step-by-step explanation:
you have to add them all up because it says find the range
