Answer:
There is something that looks like a paper clip and you put your photos there.
Answer:
both fireworks will explode 4.5 seconds after Firework B launches
Step-by-step explanation:
Given;
speed of firework A,
= 360 ft/s
speed of firework B,
= 340 ft/s
If the two fireworks explodes at the same height, then the height attained by the two fireworks are equal.
let the distance traveled by each firework before explosion = d
Distance = speed x time
Distance A = Distance B
speed A x time = speed B x time
let the time both fireworks explodes after Firework B launches = t
(
) t = (
) t
360t = 340t
if firework B is launched 0.25 s before Firework A, for the time of the two fireworks to be equal since we are considering time (t) after 0.25 seconds, we will have;
360(t-0.25) = 340t
360t - 90 = 340t
360 t - 340 t = 90
20 t = 90
t = 90/20
t = 4.5 seconds
Therefore, both fireworks will explode 4.5 seconds after Firework B launches
Answer:
1782 cm³
Step-by-step explanation:
First, you measure the volume of the cuboid as a whole which is length x breadth x height, 9 x 12 x 18 = 1944 cm³. Then measure the volume occupied by the space, 3 x 3 x 18 since the hole runs along the entire length = 162 cm³.
Then you subtract the volume occupied by the hole from the volume of the cuboid in total, 1944 - 162 = 1782 cm³
1 km=0.62 mi
45 km- x mi
x=45*0.621*1=27.95
Answer <span>B)27.96miles</span>