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nata0808 [166]
3 years ago
13

Find SV. It’s hard for me :(

Mathematics
1 answer:
rosijanka [135]3 years ago
5 0

Answer:

56

Step-by-step explanation:

from theorem , VR/SR=VU/UT

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Which expression is equivalent to 6 x + 8?
murzikaleks [220]
2(3x+4) you multiply 2 times 3x and 2 times 4 which gives you 6x+8
8 0
3 years ago
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Assume that the sales of a certain appliance dealer can be approximaed y sraig were $6000 in 1982 and $ 64,000 in 1987. Let x -
viktelen [127]

Answer:

y=11,600x+6,000

Yearly sales in 1990: $98,800.

Step-by-step explanation:

We have been given that the sales of a certain appliance dealer can be approximated by a straight line. Sales were $6000 in 1982 and $ 64,000 in 1987.

If at 1982, x=0 then at 1987 x will be 5.

Now, we have two points (0,6000) and (5,64000).

\text{Slope}=\frac{64,000-6,000}{5-0}

\text{Slope}=\frac{58,000}{5}

\text{Slope}=11,600

Now, we will represent this information in slope-intercept form of equation.

y=mx+b, where,

m = Slope,

b = Initial value or y-intercept.

We have been given that at x=0, the value of y is 6,000, so it will be y-intercept.

Substitute values:

y=11,600x+6,000

Therefore, the equation S=11,600x+6,000 represents yearly sales.

Now, we will find difference between 1990 and 1982.

1990-1982=8

To find yearly sales in 1990, we will substitute x=8 in the equation.

S=11,600(8)+6,000

S=92,800+6,000

S=98,800

Therefore, the yearly sales in 1990 would be $98,800.

6 0
3 years ago
Which of the tables represents a function?<br><br> 1. Table A 2. Table B 3. Table C 4. Table D
rosijanka [135]

Table D because the  x values don’t repeat

7 0
3 years ago
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the perimeter of the floor of a room is 18 metre and its height is 3 cm what is the area of 4 walls of the room​
Lina20 [59]

Note: The height of the room must be 3 m instead of 3 cm because 3 cm is too small and it cannot be the height of a room.

Given:

Perimeter of the floor of a room = 18 metre

Height of the room = 3 metre

To find:

The area of 4 walls of the room.

Solution:

We know that, the area of 4 walls of the room is the curved surface area of the cuboid room.

The curved surface area of the cuboid is

C.S.A.=2h(l+b)

Where, h is height, l is length and b is breadth.

Perimeter of the rectangular base is 2(l+b). So,

C.S.A.=\text{Perimeter of the base} \times h

Putting the given values, we get

C.S.A.=18\times 3

C.S.A.=54

Therefore, the area of 4 walls of the room is 54 sq. metres.

7 0
3 years ago
Find the perimeter if a = 1 b = 4 c = 6 d = 5
g100num [7]

Answer:16

Step-by-step explanation:

Add each side togeather

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