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wolverine [178]
3 years ago
6

What is the radius of a circle with a circumference measuring 24π cm

Mathematics
1 answer:
xeze [42]3 years ago
6 0
Your answer would be r = 3.82
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Anyone knows this?!? ​
IRINA_888 [86]

Answer:

(0.84, 0.88)

Step-by-step explanation:

if you round 0.875 you get 0.88

8 0
2 years ago
8^(x+4)=2^x..........
Ludmilka [50]

Answer:

Step-by-step explanation:

x = 0

6 0
3 years ago
Define z_alpha to be a z-score with an area of alpha to the right. For Example: z_0.10 means P(Z > z_0.10) = 0.10. We would a
Reptile [31]

Answer:

a) P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

"=NORM.INV(0.025,0,1)"

And for this case the two values are :z_{crit}= \pm 1.96

b) P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates \alpha/2 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

c) For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got z_{\alpha/2}=1.64

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Part a

P(-z_0.025 < Z < z_0.025)

For this case we want a quantile that accumulates 0.025 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(0.025,0,1)"

"=NORM.INV(0.025,0,1)"

And for this case the two values are :z_{crit}= \pm 1.96

Part b

P(-z_{\alpha/2} < Z < z_{\alpha/2})

For this case we want a quantile that accumulates \alpha/2 of the area on the tails of the normal standard distribution, and for this case we can calculate the z value with the following excel codes:

"=NORM.INV(alpha/2,0,1)"

"=NORM.INV(alpha/2,0,1)"

Part c

For this case we want to find a value of z that satisfy:

P(Z > z_alpha) = 0.05.

And we can use the following excel code:

"=NORM.INV(0.95,0,1)"

And we got z_{\alpha/2}=1.64

6 0
3 years ago
Please help I don’t understand how to do these
steposvetlana [31]

Answer:

I think there would be 86 blue marbles

x=4(106 - x ) + 6

x= 424 - 4x + 6

5x= 430

x= 86 blue marbles

Tell me if I'm wrong, hope this helps.

3 0
3 years ago
Joseph invested $16,000 in an account paying an interest rate of 5.7% compounded
Natasha_Volkova [10]

Answer: 34767.2

Step-by-step explanation:

given p = $16,000, n = 14 years, y = 5.7%

amount in bank after 14 years = p ( 1 + </100)

= 16,000 (1 + 5.7/ 100) 14

= 34767.2

5 0
3 years ago
Read 2 more answers
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