Answer:
1.08 × 10^11
Step-by-step explanation:
Subtract: (1.8*10^11)-(7.2*10^10)
Refer to the figure given below while reading the solution.
Suppose the dog reaches position A when traveled 10 m diagonally towards the opposite side.
And then position B when traveled 5 m towards the right turning 90°.
We can observe that APC is a right triangle with legs of equal length AC. And the coordinates of the point A is (AC, AC).
Also we can observe that APB is a right triangle with legs of equal length AD. Then the coordinates of the point D is (AC, AC-AD).
Hence, the coordinates of B will be (AC+AD, AC-AD).
Now, we since we have the coordinates we can calculate the shortest distances of B from each of the sides.
- The shortest distance of B from PQ = AC-AD
- The shortest distance of B from SR = 44-(AC-AD)
- The shortest distance of B from SP = AC+AD
- The shortest distance of B from RQ = 44-(AC+AD)
So, the average of the shortest distances of B from each side is 
Hence, the average of the shortest distance of B from each side is 22 m
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Step-by-step explanation:
3. The triangle that makes up the square is a 45-90-45 triangle so x = 45°. Using Pythagorean theorem,
2y^2 = 12 ---> y^2 = 6
or
y = √6
4.This is an equilateral triangle of side 11 so
y = 11/2
To find x, use the definition of sine 60:
sin 60° = opp/hyp
= x/11
or
x = 11sin60° = (11√3)/2
1 quart = 2 pints
720/2 = 360 quarts per hour
1 hour = 60 minutes
360/60 = 6 quarts per minute
1/2 divide by 3 or 1/[2(3)] which will be equal to 1/6