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vfiekz [6]
3 years ago
10

Is 143 and 63 relatively prime numberd

Mathematics
1 answer:
Igoryamba3 years ago
4 0
Yes 143 and 63 are relatively prime because they have no prime factors in common   

brainliest answer please?
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Why is it important to consider scale when graphing inequalities?
Olegator [25]

Because to get a straight line you need a scale. Otherwise you will not be able to graph a straight line.

6 0
3 years ago
Evaluate.<br> x+1/3<br> when x = -2.5<br> O 0.5<br> O -0.5<br> O 1.167<br> O-1
mario62 [17]

Answer:

-.5

Step-by-step explanation:

(x+1)/3

Let x = -2.5

(-2.5+1)/3

Parentheses first

-1.5/3

-.5

6 0
3 years ago
Read 2 more answers
1. Let a; b; c; d; n belong to Z with n &gt; 0. Suppose a congruent b (mod n) and c congruent d (mod n). Use the definition
lukranit [14]

Answer:

Proofs are in the explantion.

Step-by-step explanation:

We are given the following:

1) a \equi b (mod n) \rightarrow a-b=kn for integer k.

1) c \equi  d (mod n) \rightarrow c-d=mn for integer m.

a)

Proof:

We want to show a+c \equiv b+d (mod n).

So we have the two equations:

a-b=kn and c-d=mn and we want to show for some integer r that we have

(a+c)-(b+d)=rn. If we do that we would have shown that a+c \equiv b+d (mod n).

kn+mn   =  (a-b)+(c-d)

(k+m)n   =   a-b+ c-d

(k+m)n   =   (a+c)+(-b-d)

(k+m)n  =    (a+c)-(b+d)

k+m is is just an integer

So we found integer r such that (a+c)-(b+d)=rn.

Therefore, a+c \equiv b+d (mod n).

//

b) Proof:

We want to show ac \equiv bd (mod n).

So we have the two equations:

a-b=kn and c-d=mn and we want to show for some integer r that we have

(ac)-(bd)=tn. If we do that we would have shown that ac \equiv bd (mod n).

If a-b=kn, then a=b+kn.

If c-d=mn, then c=d+mn.

ac-bd  =  (b+kn)(d+mn)-bd

          =    bd+bmn+dkn+kmn^2-bd

          =           bmn+dkn+kmn^2

          =            n(bm+dk+kmn)

So the integer t such that (ac)-(bd)=tn is bm+dk+kmn.  

Therefore, ac \equiv bd (mod n).

//

3 0
3 years ago
From a distance of 110 m, the angle of elevation to the top spire of a tower is 35°.
Nady [450]

Answer:

  77 m

Step-by-step explanation:

The geometry can be modeled by a right triangle. The distance from the viewpoint to the base of the tower is 110 m, the leg of the triangle adjacent to the angle. The height of the spire is the leg of the triangle opposite the given angle. The relevant trig relation is ...

  Tan = Opposite/Adjacent

__

Using the given numbers, we find ...

  tan(35°) = height/(110 m)

  height = (110 m)tan(35°) = (110 m)×0.700208 ≈ 77.0 m

The height of the tower is about 77 meters.

3 0
2 years ago
Solve the following equation for x.<br><br> 28.8 = 1.8x
Alisiya [41]

Answer:

x=16

Step-by-step explanation:

28.8 / 1.8 is 16.

7 0
3 years ago
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