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vfiekz [6]
3 years ago
10

Is 143 and 63 relatively prime numberd

Mathematics
1 answer:
Igoryamba3 years ago
4 0
Yes 143 and 63 are relatively prime because they have no prime factors in common   

brainliest answer please?
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What is the value of the element at h21?
Marysya12 [62]
I think that's the element on the second row and the first column  which is 15.
8 0
3 years ago
What are two numbers that multiply for 54 and add to give you -3
cupoosta [38]

Answer:

9 and -6 multiply to -54 and add to 3

Step-by-step explanation:

when listing the factors of 54, we can find a pair that add to 3

1, 2, 3, 6, 9, 18, 27 and 54

9 and -6 is the pair.

hope this helps! :D

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3 0
3 years ago
PLZ ANSWER ILL GIVE BRAINILEST2 box plots. The number line goes from 26 to 36. For Pleasantville Middle School, the whiskers ran
Svetach [21]

Answer:

I believe the answer is- The mean and MAD can accurately describe the "typical" value in the symmetric data set.

Step-by-step explanation:

The other answers don't make sense because the mean and MAD are being used for symmetrical distributions and asymmetrical means uneven distributions.

6 0
3 years ago
Read 2 more answers
The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.
mote1985 [20]

The confidence interval for the mean usage of water is (18.7,20.5).

Given population standard deviation of 2.4, mean of 19.5 gallons per day and confidence interval of 98%.

We have to find the confidence interval for the mean usage of water.

To find out the confidence interval we have to first find margin of error.

μ=19.5

σ=2.4

α=0.98

α/2=0.49

We have to find the z value for the p value 0.49 which is z=2.33

Margin of error=z*μ/\sqrt{n}

=2.33*19.5/\sqrt{3034}

=0.82

lower level=mean -m

=19.5-0.82

=18.68

after rounding upto 1 decimal

=18.7

upper mean = mean+m

=19.5+0.82

=20.52

Hence the confidence interval for the usage of water is (18.7,20.52).

Learn more about margin of error at brainly.com/question/10218601

#SPJ4

7 0
2 years ago
In a study of automobile collision insurance costs, a random sample of n = 35 repair costs of front-end damage caused by hitting
laiz [17]

Answer: The maximum error = $105.76.

Step-by-step explanation:

Formula to find the maximum error:

E= z^*\dfrac{\sigma}{\sqrt{n}}

, where n= sample size.

\sigma = Population standard deviation

z*= Critical value(two-tailed).

As per given  , we have

\overline{x}=1438

n= 35

\sigma=269

For 98% confidence  , the significance level = 1-0.98=0.02

By z-table , the critical value (two -tailed) =z^* = z_{\alpha/2}=z_{0.01}=2.326

Now , the maximum error = E= (2.326)\dfrac{269}{\sqrt{35}}

E= (2.326)\dfrac{269}{5.9160797831}

E= (2.326)\times45.4692989044=105.761589252\pprox105.76

Hence, With 98% confidence level , the maximum error = $105.76.

4 0
3 years ago
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