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3 years ago

Is 143 and 63 relatively prime numberd

Mathematics

1 answer:

Igoryamba3 years ago

4 0

Yes 143 and 63 are relatively prime because they have no prime factors in common

brainliest answer please?

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What is the value of the element at h21?

Marysya12 [62]

I think that's the element on the second row and the first column which is 15.

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3 years ago

What are two numbers that multiply for 54 and add to give you -3

cupoosta [38]

Answer:

9 and -6 multiply to -54 and add to 3

Step-by-step explanation:

when listing the factors of 54, we can find a pair that add to 3

1, 2, 3, 6, 9, 18, 27 and 54

9 and -6 is the pair.

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3 years ago

PLZ ANSWER ILL GIVE BRAINILEST2 box plots. The number line goes from 26 to 36. For Pleasantville Middle School, the whiskers ran

Svetach [21]

Answer:

I believe the answer is- The mean and MAD can accurately describe the "typical" value in the symmetric data set.

Step-by-step explanation:

The other answers don't make sense because the mean and MAD are being used for symmetrical distributions and asymmetrical means uneven distributions.

6 0

3 years ago

Read 2 more answers

The water works commission needs to know the mean household usage of water by the residents of a small town in gallons per day.

mote1985 [20]

The confidence interval for the mean usage of water is (18.7,20.5).

Given population standard deviation of 2.4, mean of 19.5 gallons per day and confidence interval of 98%.

We have to find the confidence interval for the mean usage of water.

To find out the confidence interval we have to first find margin of error.

μ=19.5

σ=2.4

α=0.98

α/2=0.49

We have to find the z value for the p value 0.49 which is z=2.33

Margin of error=z*μ/ $\sqrt{n}$

=2.33*19.5/ $\sqrt{3034}$

=0.82

lower level=mean -m

=19.5-0.82

=18.68

after rounding upto 1 decimal

=18.7

upper mean = mean+m

=19.5+0.82

=20.52

Hence the confidence interval for the usage of water is (18.7,20.52).

Learn more about margin of error at brainly.com/question/10218601

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7 0

2 years ago

In a study of automobile collision insurance costs, a random sample of n = 35 repair costs of front-end damage caused by hitting

laiz [17]

Answer: The maximum error = $105.76.

Step-by-step explanation:

Formula to find the maximum error:

$E= z^*\dfrac{\sigma}{\sqrt{n}}$

, where n= sample size.

$\sigma$ = Population standard deviation

z*= Critical value(two-tailed).

As per given , we have

$\overline{x}=1438$

n= 35

$\sigma=269$

For 98% confidence , the significance level = $1-0.98=0.02$

By z-table , the critical value (two -tailed) = $z^* = z_{\alpha/2}=z_{0.01}=2.326$

Now , the maximum error = $E= (2.326)\dfrac{269}{\sqrt{35}}$

$E= (2.326)\dfrac{269}{5.9160797831}$

$E= (2.326)\times45.4692989044=105.761589252\pprox105.76$

Hence, With 98% confidence level , the maximum error = $105.76.

4 0

3 years ago