Answer:
197.2 million
Step-by-step explanation:
The appropriate exponential equation for the population is ...
p(t) = 172.0e^(0.019t)
Then we can compute for t=7.2:
p(7.2) = 172.0e^(0.019·7.2) ≈ 172.0·1.146599 ≈ 197.2
7.2 minutes from now, the population will be about 197.2 million.
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For continuous growth (or continuous compounding), the exponential formula is ...
f(t) = (value at t=0)×e^(rt)
where r is the growth rate in one unit of time, and t is the number of time periods.
So for this question, we're asked to find the quadrant in which the angle of data lies and were given to conditions were given. Sign of data is less than zero, and we're given that tangent of data is also less than zero. Now I have an acronym to remember which Trig functions air positive in each quadrant. . And in the first quadrant we have that all the trig functions are positive. In the second quadrant, we have that sign and co seeking are positive. And the third quadrant we have tangent and co tangent are positive. And in the final quadrant, Fourth Quadrant we have co sign and seeking are positive. So our first condition says the sign of data is less than zero. Of course, that means it's negative, so it cannot be quadrant one or quadrant two. It can't be those because here in Quadrant one, we have that all the trick functions air positive and the second quadrant we have that sign. If data is a positive, so we're between Squadron three and quadrant four now. The second condition says the tangent of data is also less than zero now in Quadrant three. We have that tangent of data is positive, so it cannot be quadrant three, so our r final answer is quadrant four, where co sign and seek in are positive.
Answer:
any score that lies between 88.8 and 97.2 is within one std. dev. of the mean
Step-by-step explanation:
One std. dev. above the mean would be 93 + 4.2, or 97.2. One std. dev. below the mean would be 93 - 4.2, or 88.8.
So: any score that lies between 88.8 and 97.2 is within one std. dev. of the mean.
The first interception for this function would be at (1,0) the next would be (4,0)