Carol buys a house for £234 900

Does the construction demonstrate how to copy an angle correctly using technology?

Ksivusya [100]

Answer:

No, the distance between points A and F was used to create circle H.

Step-by-step explanation:

In the given example the points F and G are the radius of the circle H. The distance from point A to point F is used to draw the circle H. The center point for circle H is point A. The circle is the copied and the angles are used to create another circle.

4 0

3 years ago

In Mohammad’s class, 80% of the students are boys. There are 24 boys in the class. What is the total number of students in Moham

irina1246 [14]

Answer:

30 students

Step-by-step explanation:

80% of N = 24 where N is the total number of students

So

.80 N = 24

N = 24 / .80 = 30

sorry this was a late response

6 0

3 years ago

20. The surface areas of two similar solids are 216 m² and 1014 m². The volume of the larger one is 2197 m³. What is the volume

Andrei [34K]

Answer:

216 m³

Step-by-step explanation:

The ratio of linear dimensions is the square root of the ratio of area dimensions.

s = √(216/1014) = √(36/169) = 6/13

Then the ratio of volume dimensions is the cube of that. The smaller volume is ...

v = (6/13)³·2197 m³ = 216/2197·2197 m³ = 216 m³

The volume of the smaller solid is 216 m³.

8 0

3 years ago

For g(x)=1/2x-11, find x when g(x)=-5

Vesna [10]

Answer:

x = 12

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Function Notation

Step-by-step explanation:

Step 1: Define

g(x) = 1/2x - 11

g(x) = -5

Step 2: Solve for x

Substitute: -5 = 1/2x - 11
Isolate x term: 6 = 1/2x
Isolate x: 12 = x
Rewrite: x = 12

7 0

2 years ago

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$