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a_sh-v [17]
2 years ago
9

Please help, it is a bonus problem so you don't have to show your work. But I would like to see it.

Mathematics
2 answers:
BartSMP [9]2 years ago
7 0

In a quadratic equation, the formula is:  ax^2 + bx + c = 0

In the given formula 2x^2 + 4x -6 = 0:

a = 2, b = 4 and c = -6

Using the quadratic formula x1, x2 = -b+/-sqrt(b^2-4ac)/2a

Replace am b and c with their values and solve:

Now you have the 2 x values :

x1 = 1, x2 = -3

1^2 + -3^2 = 1 + 9 = 10

Answer: 10

solniwko [45]2 years ago
3 0

Answer:

10

Step-by-step explanation:

→ Factorise equation

( 2x + 6 ) ( x - 1 )

→ Solve

x = -3 and 1

→ Find the value

(-3)² + (1)² = 10

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If the perimeter of this quadrilateral (2ft 13ft 15in this is the quadrilateral) is 79 inches, what is the measure of the missin
kumpel [21]

Answer:

The missing side length is 27 in

Step-by-step explanation:

see the attached figure

we know that

1 ft= 12 in

step 1

Convert ft to in

2 ft=2*12=24 in

Note ----> the given measure is 13 in instead of 13 ft

step 2

Find the missing side length

The perimeter of a quadrilateral is the sum of its four side lengths

Let

x------> the missing side length

P=x+24+13+15

P=79 in

so

79=x+24+13+15

x=79-52=27 in

The missing side length is 27 in

7 0
3 years ago
What is the answer to 2.5 divided by 5
kondaur [170]
The answer is 0.5


2.5/5=0.5
8 0
2 years ago
I need help please help me quick
sergejj [24]

Count the squares in between each letter.

Point Q is 6 units from Point R

Point R is 7 units from Point T

Point T is 3 units from Point S

For the area, it is easiest to take the area of each of those shapes and then add them.

(3*7/2) + (6*7)

10.5 + 42 = 52.5 Square Units

3 0
3 years ago
A recursive rule for a geometric sequence is a1=2; an= 4/9 an-1
Oxana [17]

A recursive rule for a geometric sequence:

a_1\\\\a_n=r\cdot a_{n-1}

---------------------------------------------------

a_1=2;\ a_n=\dfrac{4}{9}a_{n-1}\to r=\dfrac{4}{9}

---------------------------------------------------

The exciplit rule:

a_n=a_1r^{n-1}

Substitute:

a_n=2\left(\dfrac{4}{9}\right)^{n-1}=2\cdot\left(\dfrac{4}{9}\right)^n\cdot\left(\dfrac{4}{9}\right)^{-1}=2\cdot\left(\dfrac{4}{9}\right)^n\cdot\dfrac{9}{4}\\\\\boxed{a_n=\dfrac{9}{2}\cdot\left(\dfrac{4}{9}\right)^n}

3 0
3 years ago
PLEASE HELP ME JUST A LITTLE CONFUSED.
Usimov [2.4K]

The answer is

2(5x-6)≤x+24

3 0
3 years ago
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