1.1x+1.2x-5.4=-10
11/10x+12/10x-54/10=10
11x/2.5+2^2-1*3/5x-3^3/5=-10
(11x)+2(2*3x)+2(-3^3)/2*5=-10
11x+2(6x)+2(-27)/2*5=-10
11x+2*6x-2*27/2*5=-10
11x+12x-54/2*5=-10
23x-54/2*5=-10
23x-54=-100
23x=-46
23x/23=-46/23
x=-2*23/23
x=-2
Answer:
22.38 g of silicone-32 will be present in 300 years.
Step-by-step explanation:
A radioactive half-life refers to the amount of time it takes for half of the original isotope to decay and its given by

where,
= quantity of the substance remaining
= initial quantity of the substance
= time elapsed
= half life of the substance
From the information given we know:
- The initial quantity of silicone-32 is 30 g.
- The time elapsed is 300 years.
- The half life of silicone-32 is 710 years.
So, to find the quantity of silicone-32 remaining we apply the above equation

22.38 g of silicone-32 will be present in 300 years.
240, you just add a zero to 24, I don't know what you mean by zero the hero of 4 square, hope this helps!
Answer:
2+2=4
Step-by-step explanation:
Answer:
Step-by-step explanation:
Here you go mate
Step 1
6x-8=5x+4 Equation/Question
Step 2
6x-8=5x+4 simplify
6x-8=5x+4
Step 3
6x-8=5x+4 Subtract
x-8=4
Step 4
x-8=4 Add 8
answer
x=12
Hope this helps