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a_sh-v [17]
2 years ago
9

Please help, it is a bonus problem so you don't have to show your work. But I would like to see it.

Mathematics
2 answers:
BartSMP [9]2 years ago
7 0

In a quadratic equation, the formula is:  ax^2 + bx + c = 0

In the given formula 2x^2 + 4x -6 = 0:

a = 2, b = 4 and c = -6

Using the quadratic formula x1, x2 = -b+/-sqrt(b^2-4ac)/2a

Replace am b and c with their values and solve:

Now you have the 2 x values :

x1 = 1, x2 = -3

1^2 + -3^2 = 1 + 9 = 10

Answer: 10

solniwko [45]2 years ago
3 0

Answer:

10

Step-by-step explanation:

→ Factorise equation

( 2x + 6 ) ( x - 1 )

→ Solve

x = -3 and 1

→ Find the value

(-3)² + (1)² = 10

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Evaluate 7w-14 for w=9.
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5 0
3 years ago
Using the quadratic formula to solve 11x²-4x=1 What are The values of X?
Anvisha [2.4K]
11x^2 - 4x = 1
11x^{2} - 4x - 1 = 1 - 1
11x^{2} - 4x - 1 = 0
x = \frac{-(-4) \± \sqrt{(-4)^{2} - 4(11)(-1)}}{2(11)}
x = \frac{4 \± \sqrt{16 + 44}}{22}
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8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B5%5D%7B833%7D%20" id="TexFormula1" title=" \sqrt[5]{833} " alt=" \sqrt[5]{833} "
zepelin [54]
Here is the simplified answer to this equation: 5 goes into 8 once, so you would bring the 5 on top and subtract 8, the first number, by 5. The answer is three. Bring down the 3 next to the 8. You now have 33. 5 goes into 33 6 times, which equals 30. Write 30 underneath 33 and bring the 6 to the top next to the 1. Bring down the 3 next to the last 3. You now have 33. 5 goes into 33 (once again) 6 times. Write 6 on top next to the last 6. 33 - 30 = 3. 5 cannot go into 3 since it is larger, so 3/5 you write 3/5 as a decimal next to 166 at the top (3 at the bottom and 5 is the larger number at the divisor spot). The decimal is 0.6. Therefore, your answer should be 166.6. To make sure, multiply 166.6 x 5. Hopefully, you get 833.

Hope I helped!
4 0
2 years ago
A trapezoid has an area of 184 in^2. The height is 8 in and the length of one base is 16 in. Write and solve an equation to find
inna [77]

Answer:

The length of other base is <u>30 in</u>.

Step-by-step explanation:

Given:

A trapezoid has an area of 184 in^2. The height is 8 in and the length of one base is 16 in.

Now, to get the length of other base.

Let the length of other base be  (b).

Area of trapezoid (Area) = 184 in².

Height of trapezoid (h) = 8 in.

Length of one base (a) = 16 in.

Now, to get the length of other base of trapezoid we solve an equation:

Area=\frac{(a+b)}{2} h

184=\frac{(16+b)}{2}\times 8

184=(16+b)\times 4

<em />184=64+4b<em />

<em>Subtracting both sides by 64 we get:</em>

<em />120=4b<em />

<em>Dividing both sides by 4 we get:</em>

30=b\\\\b=30\ in.

Therefore, the length of other base is 30 in.

3 0
3 years ago
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