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inna [77]
2 years ago
11

Pls help quick! I am not sure if i did this right

Mathematics
2 answers:
bogdanovich [222]2 years ago
7 0

Answer: The last option, <u>28</u> minutes

Step-by-step explanation:

    See attached for my work. <em>If you are color blind let me know, I color-coded where I "pulled" numbers from.</em>

    To answer this problem, we can look at the graph. We need to see for how long the black line is above the blue.

Pie2 years ago
7 0

Answer:

28 minutes

Step-by-step explanation:

Hello!

The black line represents Lynn's speed throughout the course of the run, while the blue line represents Kael's run throughout the run.

The y-values of the graph represent the speed of each person, while the x-values represent the time.

To find out how long Lynn was running faster than Kael, we can find the range of the x-values when the black line is ABOVE the blue line.

The first point when it was above the blue line is when x is at 12. The final point is when x is at 40.

<h3>Subtract:</h3>
  • 40 - 12
  • 28

Since the units are minutes, Lynn was faster than Kael for 28 minutes.

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560+ 147= 707

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14+ 14(1/2)=21
21(7)= 147
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3 years ago
Find the measure of ∠. Show your work.
poizon [28]

Answer:

77

Step-by-step explanation:

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5 0
4 years ago
a baseball team has home games on Friday and Saturday. the two games together earn 3979.00 for the team. Fridays game generates
mojhsa [17]
3979.00-781.00= 3198.00 is how much money was taken in at each game
8 0
3 years ago
At birth, one puppy weighs 15/16 pounds. A second puppy weighs 1 and 1/8 pounds. How much more did the second puppy weigh?
zvonat [6]

Answer:

3/16 pounds more.

Step-by-step explanation:

It is 1 1/8 - 15/16

= 9/8 - 15/16

= 18/16 - 15/16

=  3/16.

5 0
2 years ago
What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*
pickupchik [31]
<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation x^4-41x^2=-400.

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

x^4-41x^2+400=-400+400.

x^4-41x^2+400=0.

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

x^4-25x^2-16x^2+400=0

Making it into two groups, we get

(x^4-25x^2)+(-16x^2+400)=0

Factoring out GCF of each group, we get

x^2(x^2-25)-16(x^2-25)=0

(x^2-25)(x^2-16) =0

Factoring out  (x^2-25) and (x^2-16) separately by difference of the squares identity a^2-b^2=(a-b)(a+b), we get

(x^2-25) = x^2-5^2= (x-5)(x+5) and

x^2-16 = x^2-4^2 =(x-4)(x+4).

Therefore,

(x-5)(x+5)(x-4)(x+4) =0

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>
6 0
3 years ago
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