We are given
number of heads =15
we know that
any healthy dragon has three heads
horse has 1 head
chicken has 1 head
Let's assume
number of dragons is x
number of horses is y
number of chickens is z
so, we will get
first equation:

number of legs =50
any healthy dragon has four legs
chicken has 2 legs
horse has four legs
so, we can get second equation as

we can simplify it


now, we can find third equation
dragon has two wings
horse has no wings
chicken has two wings
so, we will get third equations as

now, we can simplify it



so, we will get system of equations as



now, we can use substitution
We can find for z from third equation

we can plug this in first equation

now, we can solve for y


now, we can plug this z and y into second equation

now, we can solve for x



now, we can find y and z

we can plug x=1



we can plug x=1


Hence ,
number of dragons is 1
number of horses is 11
number of chicken is 1............Answer
15376
/ I
961 16
/ I / I
31 31 4 4
31 × 4 = 124
The square root of 15376 is 124
So, 4 will be multiplicated by 72 and the result will be divided by 21 giving you 13.71 (I'm not sure about this answer)
So for H I want to say the second one because it is spread out.
Given:
Mason throws a coin 3 times.
The outcome of each throw is either Heads or Tails.
To find:
The list of all the possible outcomes of the 3 throws.
Solution:
Let H represents heads and T represents tails.
For each throw we have 2 choices either H or T.
For three throws the total number of possible outcomes is
Now, list the possible outcomes as shown below.
HHH, HHT, HTH, HTT, THH, THT, TTH, TTT
Therefore, the list of 8 possible outcomes is HHH, HHT, HTH, HTT, THH, THT, TTH, TTT.