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NeX [460]
2 years ago
8

Solve the following inequality: ALGEBRA 1

Mathematics
1 answer:
Alexxandr [17]2 years ago
6 0

Answer:

m \leqslant 10 \: or \: m > 4

Step-by-step explanation:

\frac{m - 2}{3}  \leqslant  - 4 \\  \frac{m - 2}{3}  \times 3 \leqslant -  4 \times 3 \\ m - 2 \leqslant  - 12 \\ m - 2 + 2 \leqslant  - 12 + 2 \\ m \leqslant 10

OR

3m - 8 > 4 \\ 3m - 8 + 8 > 4 + 8 \\ 3m > 12 \\  \frac{3m}{3}  > \frac{12}{3} \\ m > 4

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Write the expression 2 x 8 + 20 - 12 ÷ 6 with parentheses and brackets two different ways so one value is less than 10 and the o
Marizza181 [45]

Greater than 50:

2 x (8 + 20 - 12 / 8) is 52

Less than 10:

2 x (8 +(20 - 12)) ÷ 6 is 5.33

4 0
3 years ago
WILL MARK BRAINLIST PLS HELP
nydimaria [60]

Answer:

The second option - 8/81

Step-by-step explanation:

6 0
3 years ago
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A varsity cross-country team runs on a course that makes a right turn after 3 miles, and continues on one mile less than the jun
Dmitry [639]
3:4:5 triangle, The junior varsity team's course is 5 miles
5 0
3 years ago
Read 2 more answers
2 in 1
ollegr [7]
1)
2x^2 - 13x - 24 = 0;
the discriminant is : ( - 13 )^2 - 4 * 2 * ( -24 ) = 169 +  192 = 361 = 19^2 => we have two different rational-number solutions ;

2) 
[ -2( x + 2 ) - 3( x - 5 ) ] / [ ( x - 5 )( x + 2 ) ] < 0 <=>

( -5x + 11 ) /  [ ( x - 5 )( x + 2 ) ] < 0

We have 2 situations :
a)  - 5x + 11 < 0 and  ( x - 5 )( x + 2 ) > 0 => x∈ ( 11 / 5 , + oo ) and x∈( -oo, - 2 )U
( 5 , + oo ) => x∈( 5, +oo);
b)   - 5x + 11 >  0 and  ( x - 5 )( x + 2 ) <  0 => x∈(-oo, 11/5) and x∈( -2, 5 ) =>
x∈( -2, 11/5 );

Finally, x∈ U (-2, 11 / 5 ) U ( 5, +oo).
3 0
3 years ago
4a – 16 = a - 15 how do I solve ​
miv72 [106K]

Answer:

a = \frac{1}{3}

Step-by-step explanation:

4a -16 = a - 15

both left and right -a

then

4a - 16 -a = a - 15 -a

then

4a -a -16 = a -a -15

then

3a -16 = -15

both left and right + 16

then

3a -16 + 16 = -15 + 16

then

3a = 1

both left and right ÷3

then

3a ÷ 3 =1 ÷ 3

then

a = \frac{1}{3}

8 0
3 years ago
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