Answer:
He is αβ 60° and 30° i need some in my answers 5 brain list answers
Answer:
1.) Triangle ABC is congruent to Triangle CDA because of the SAS theorem
2.) Triangle JHG is congruent to Triangle LKH because of the SSS theorem
Step-by-step explanation:
Alright. Let's start with the 1st figure. How do we prove that triangles ABC and CDA (they are named properly) are congruent? First, we can see that segments BC and AD have congruent markings, so that can help us. We also see a parallel marking for those segments as well, meaning that the diagonal AC is also a transversal for those parallel segments. That means we can say that angle CAD is congruent to angle ACB because of the alternate interior angles theorem. Then, the 2 triangles also share the side AC (reflexive property).
So, we have 2 congruent sides and 1 congruent angle for each triangle. And in the way they are listed, this makes the triangles congruent by the SAS theorem since the angle is adjacent to the 2 sides that are congruent.
The second figure is way easier. As you can clearly see by the congruent markings on the diagram, all the sides on one triangle are congruent to the other. So, since there are 3 sides congruent, we can say the triangles JHG and LKH are congruent by the SSS theorem.
The paper is 7 cm by (x + 8) cm.
A photo is 5 cm by (x + 6) cm, and is printed in the middle of the paper.
The area of the border/space around the photo is 50 cm².
To find the area of the border around the photo, you find the area of the paper and subtract it by the area of the photo.
The area of the paper:
A = 7 · (x + 8)
The area of the photo:
A = 5 · (x + 6)
Your equation to find the area of the border around the photo is:
(7 · (x + 8)) - (5 · (x + 6)) = A
[area of paper - area of photo = area of border]
Since you know the area of the border, you can plug it in:
(7 · (x + 8)) - (5 · (x + 6)) = 50
Multiply the 7 into (x + 8), and multiply the 5 into (x + 6)
(7x + 56) - (5x + 30) = 50
Distribute/multiply the - to (5x + 30)
7x + 56 - 5x - 30 = 50
Combine like terms
2x + 26 = 50
Subtract 26 on both sides
2x = 24
Divide 2 on both sides
x = 12
F(x) = 3x+1
put x = a+h
f(a+h) = 3(a+h) + 1
f(a+h) = 3a + 3h + 1
put x = a
f(a) = 3a + 1
f(a+h)-f(a) = 3a + 3h + 1 -(3a+1)
f(a+h)-f(a) = 3a +3h + 1 - 3a -1
f(a+h)-f(a) = 3h
