Answer:
9
Step-by-step explanation:
We know that
[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²
[<span>surface area of the regular triangular pyramid]=lateral area+area of the base
area of the base is equals to the area of the lateral sides because are </span>equilateral triangles
therefore
area of the base=27 ft²
[surface area of the regular triangular pyramid]=81+27----> 108 ft²
the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
Answer:
Both of them can be simplified.
Recall that 4 = 2^2.
2^7 / 4^2 = 2^7 / (2^2)^2 = 2^7 / 2^4 = 2^(7-4) = 2^3 = 8
Similarly, 2^7 / 2^4 = 2^(7-4) = 2^3 = 8
The answers to both exercises are 8.
Step-by-step explanation:
The second one is the first claim, because it is a traingles and one square.
The third one is the sond claim because they are a part of the rectangular so moving them outside of it would increase the area, I think, if that makes sense.
