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Murljashka [212]
2 years ago
12

Find the 12th term of an AP of the form 7, 12, 17, 22

Mathematics
1 answer:
Nostrana [21]2 years ago
6 0

Answer:

27

Step-by-step explanation:

The rule will be

Ni=(i-1)*5+2

  • i=1 → N=(1–1)*5+2=0*5+2=0+2=2
  • i=2 → N=(2–1)*5+2=1*5+2=5+2=7
  • i=3 → N=(3–1)*5+2=2*5+2=10+2=12
  • i=4 → N=(4–1)*5+2=3*5+2=15+2=17
  • i=5 → N=(5–1)*5+2=4*5+2=20+2=22
  • i=6 → N=(6–1)*5+2=5*5+2=25+2=27

________________

Learn more about arithmetic sequences:

  • brainly.com/question/6561461
  • brainly.com/question/503167

#SPJ2

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The sum of two consecutive integers is 345. What are the integers? need help with it
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Answer:

hi there ☺️

Here we will use algebra to find three consecutive integers whose sum is 345. We start by assigning X to the first integer. Since they are consecutive, it means that the 2nd number will be X + 1 and the 3rd number will be X + 2 and they should all add up to 345. Therefore, you can write the equation as follows:

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To solve for X, you first add the integers together and the X variables together. Then you subtract three from each side, followed by dividing by 3 on each side. Here is the work to show our math:

X + X + 1 + X + 2 = 345

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3X + 3 - 3 = 345 - 3

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Which means that the first number is 114, the second number is 114 + 1 and the third number is 114 + 2. Therefore, three consecutive integers that add up to 345 are 114, 115, and 116.

114 + 115 + 116 = 345

We know our answer is correct because 114 + 115 + 116 equals 345 as displayed above.

Step-by-step explanation:

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