Answer:
363.22
Step-by-step explanation:
<u>Method 1: </u>
You could find the whole figure surface area than divided by 1/2
<u>Method 2:</u> (the one I'm going to personally be doing)
Break the figure into two rectangular figures
Formula for surface area of rectangular prism:
A = 2(width x length + height x length + height x width)
Figure 1:
A = 2(width x length + height x length + height x width)
height = 3.8 yd
length = 10.1 yd
width = 4.3 yd
A = 2((4.3) x (10.1) + (3.8) x (10.1) + (3.8) x (4.3))
A = 2(98.15)
A = 196.3
Figure 2:
A = 2(width x length + height x length + height x width)
height = 8.4 yd
length = 10.1 yd
width = 2 yd
A = 2((2) x (10.1) + (8.4) x (10.1) + (8.4) x (2))
A = 2(121.84)
A = 243.68
There is overlapping surface area that shouldnt be include so we need to subtract it...
<u>For one face of figure 1</u>
3.8 x 10.1 = 38.38
Total:
Figure 1 + Figure 2 - 2(one face)
196.3 - 38.38 = 157.92
243.68 - 38.38 = 205.3
205.3 + 157.92 = 363.22
Answer:
A = choosing a red marble
B = choosing a green marble
Probability of A happening = P(A) = 5/(3+5+4) = 5/12
Probability of B happening = P(B) = 4/(3+5+4) = 4/12
Probability of either happening = P(A) + P(B) = 5/12 + 4/12 = 7/12
The key word in their question is red OR green and that is why we add the two probabilities. If they ask the probability of them both happening (if they said red AND green), you would multiply P(A)*P(B).
Answer: y=-5x-2
Step-by-step explanation: If you type all of the options into desmos calculator you will come up with 4 different graphs. Just simply find the graph with your coordinates on it. hope this helped :)
Answer:
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
Step-by-step explanation:
Here in this question, we want to state what will happen if the null hypothesis is true in a chi-square test.
If the null hypothesis is true in a chi-square test, discrepancies between observed and expected frequencies will tend to be small enough to qualify as a common outcome.
This is because at a higher level of discrepancies, there will be a strong evidence against the null. This means that it will be rare to find discrepancies if null was true.
In the question however, since the null is true, the discrepancies we will be expecting will thus be small and common.
Answer:
2m - 11
Step-by-step explanation:
twice m = 2m
decreased by 11 = -11
