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2 years ago

I need help please !

Mathematics

2 answers:

Natalka [10]2 years ago

7 0

It’s C I think it is

evablogger [386]2 years ago

5 0

Answer:

$D.\ 7 \frac{3}{4} * \frac{\sqrt{16} }{5} = \frac{31}{4} * \frac{4}{5} = \frac{31}{5} \\\\C. \ 7 \frac{3}{4} + \frac{\sqrt{16} }{5} =\frac{31}{4} + \frac{4}{5} = \frac{171}{20}$

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What is one twelve of 1

Sergeu [11.5K]

Answer:

1/12 of 1 =0.08333333333

Step-by-step explanation:

8 0

3 years ago

I need help understanding how to do this

Rudik [331]

Dilation with scale factor of 3= E.
translation 3 units up= D.
translation 3 units right= B.
horizontal stretch by a factor of 3= A.
vertical stretch by a factor of 3= C.

translation= its move places, so you are adding
stretch= it changes shape. you can either stretch it horizontally or vertically so you are multiplying

going up and down/ vertically is the y-axis
going left and right/horizontally is the x-axis

hope this helped!

4 0

2 years ago

Please help thanks a lot for your help

Salsk061 [2.6K]

Answer:

it's hypotenuse

then

base^2+length ^2=hypotenuse^2

5^2+9^2=106^2

11236

if wrong correct me pls

have a great day ahead

CapTainGeNius

7 0

2 years ago

Read 2 more answers

A drug company is considering marketing a new local anesthetic. The effective time of the anesthetic the drug company is current

lapo4ka [179]

Using the z-distribution, we have that:

The hypothesis test is:

$H_0: \mu = 7.4$

$H_1: \mu < 7.4$

The p-value is of 0.0668.

The critical value is $z^{\ast} = -1.28$

b) Since the test statistic is less than the critical value for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

Item a:

At the null hypothesis, it is tested if the mean is of 7.4 minutes, that is:

$H_0: \mu = 7.4$

At the alternative hypothesis, it is tested if the mean is lower than 7.4 minutes, that is:

$H_1: \mu < 7.4$

We have the standard deviation for the population, hence, the z-distribution is used.

The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

$\sigma$ is the standard deviation of the sample.

n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 7.1, \mu = 7.4, \sigma = 1.2, n = 36$ .

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{7.1 - 7.4}{\frac{1.2}{\sqrt{36}}}$

$z = -1.5$

Using a z-distribution calculator, the p-value is of 0.0668.

Also using a calculator, considering a left-tailed test, as we are testing if the mean is less than a value, the critical value with a significance level of 0.1 is of $z^{\ast} = -1.28$ .

Item b:

Since the test statistic is less than the critical value for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

You can learn more about the use of the z-distribution to test an hypothesis at brainly.com/question/16313918

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2 years ago

Round 913610 to the nearest ten

Marizza181 [45]

The next bigger ten is 913,620 .
The next smaller ten is 913,600.

913,610 is exactly in the middle between them.

913,610 is already written to the nearest ten.

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3 years ago

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