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son4ous [18]
4 years ago
8

The coordinates of rectangle ABCD are A(1, 2), B(4, 5),C(9, 0) and D(6, -3). What is the area of the rectangle?

Mathematics
2 answers:
natulia [17]4 years ago
8 0

Answer:

30 squar units

Step-by-step explanation:

puteri [66]4 years ago
5 0
 the answer is 30 Square Units.
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My sister and I each brought a bottle of sunblock to the beach. My bottle had 89ml and my sister’s had 147ml. How much more sunb
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58 more ml

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What fraction of a day is 14 hours
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What is Negative three-fourths + 2 and three-fourths
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6 0
3 years ago
Evaluate the definite integral using the graph of f(x)<br> (Image included)
Tanya [424]

a) The first integral corresponds to the area under y = f(x) on the interval [0, 3], which is a right triangle with base 3 and height 5, hence the integral is

\displaystyle \int_0^3 f(x) \, dx = \frac12 \times 3 \times 5 = \boxed{\frac{15}2}

b) The integral is zero since the areas under the curve over [3, 4] and [4, 5] are equal but opposite in sign. In other words, on the interval [3, 5], f(x) is symmetric and odd about x = 4, so

\displaystyle \int_3^5 f(x) \, dx = \int_3^4 f(x) \, dx + \int_4^5 f(x) \, dx = \int_3^4 f(x) \, dx - \int_3^4 f(x) \, dx = \boxed{0}

c) The integral over [5, 9] is the negative of the area of a rectangle with length 9 - 5 = 4 and height 5, so

\displaystyle \int_5^9 f(x) \, dx = -4\times5 = -20

Then by linearity, we have

\displaystyle \int_0^9 f(x) \, dx = \left\{\int_0^3 + \int_3^5 + \int_5^9\right\} f(x) \, dx = \frac{15}2 + 0 - 20 = \boxed{-\frac{25}2}

8 0
3 years ago
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