Answer:
f(- 2) = 13
Step-by-step explanation:
To evaluate f(- 2) substitute x = - 2 into f(x)
f(- 2) = - (- 2)³ + 2(- 2)² + (- 2) - 1
= - (- 8) + 2(4) - 2 - 1 = 8 + 8 - 2 - 1 = 13
Answer:
62
Step-by-step explanation:
Answer
given,
thickness of a flange on an aircraft component is uniformly distributed between 0.95 and 1.05 millimeters.
X = U[0.95,1.05] 0.95≤ x ≤ 1.05
the cumulative distribution function of flange
F(x) = P{X≤ x}=
=
b) P(X>1.02)= 1 - P(X≤1.02)
= 
= 0.3
c) The thickness greater than 0.96 exceeded by 90% of the flanges.
d) mean = 
= 1
variance = 
= 0.000833
The answer is 14.4
Hope it Helps :]
Use different conversion factor to accomplish the task given above,
a. (78.9x10^-13 g) x (1 x 10^12 picogram/ 1 gram) = 7.89 pg
b. (6.41x10^-10 L) x (1 x 10^9 nanoliter / 1 L) = 0.641 nL
c. (3.15x10^11 m) x ( 1 x 10^-12 terameter / 1 meter) = Tm
d. (80 x10^-19) x (1 x10^18 atto / 1) = 8 atto