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Alika [10]
3 years ago
14

In science class the students were asked to create a container to hold an egg. They would then drop the container from a window

that is 25 feet above the ground. If the equation of the containers pathway can be modeled by the equation h=-16t+25 how long will it take the container to reach the ground
Mathematics
1 answer:
belka [17]3 years ago
5 0

Answer:

It will take 1.25 seconds to reach the ground.

Step-by-step explanation:

The equation of the containers pathway can be modeled by the equation given below :

h=-16t^2+25

t is time in seconds

It is required to find the time taken by the container to reach the ground. When it reached ground, its height is equal to 0 such that,

h=0\\\\-16t^2+25=0

-16t^2=25\\\\t=\sqrt{\dfrac{25}{16}} \\\\t=1.25\ s

So, it will take 1.25 seconds to reach the ground.

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Answer:

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Explanation:

Giving the system of equations:

\begin{gathered} x+3y-z=-4\ldots\ldots\ldots\ldots\ldots\ldots..........\ldots\ldots\ldots\ldots.\ldots\text{.}\mathrm{}(1) \\ 2x-y+2z=13\ldots\ldots...\ldots\ldots\ldots\ldots..\ldots..\ldots\ldots\ldots\ldots\ldots.(2) \\ 3x-2y-z=-9\ldots\ldots\ldots.\ldots\ldots\ldots\ldots....\ldots\ldots.\ldots\ldots\ldots\text{.}\mathrm{}(3) \end{gathered}

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\begin{gathered} 3y-5(-\frac{48}{13})=-3 \\  \\ 3y+\frac{240}{13}=-3 \\  \\ 3y=-3-\frac{240}{13} \\  \\ 3y=-\frac{279}{13} \\  \\ y=-\frac{279}{39} \end{gathered}

Using the values obtained for y and z in (1), we have

\begin{gathered} x+3(-\frac{279}{39})-(-\frac{48}{13})=-4 \\  \\ x-\frac{279}{13}+\frac{48}{13}=-4 \\  \\ x-\frac{231}{13}=-4 \\  \\ x=-4+\frac{231}{13} \\  \\ x=\frac{179}{13} \end{gathered}

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