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Alika [10]
3 years ago
14

In science class the students were asked to create a container to hold an egg. They would then drop the container from a window

that is 25 feet above the ground. If the equation of the containers pathway can be modeled by the equation h=-16t+25 how long will it take the container to reach the ground
Mathematics
1 answer:
belka [17]3 years ago
5 0

Answer:

It will take 1.25 seconds to reach the ground.

Step-by-step explanation:

The equation of the containers pathway can be modeled by the equation given below :

h=-16t^2+25

t is time in seconds

It is required to find the time taken by the container to reach the ground. When it reached ground, its height is equal to 0 such that,

h=0\\\\-16t^2+25=0

-16t^2=25\\\\t=\sqrt{\dfrac{25}{16}} \\\\t=1.25\ s

So, it will take 1.25 seconds to reach the ground.

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lapo4ka [179]

Using the z-distribution, we have that:

a)

The hypothesis test is:

  • H_0: \mu = 7.4
  • H_1: \mu < 7.4

The p-value is of 0.0668.

The critical value is z^{\ast} = -1.28

b) Since the <u>test statistic is less than the critical value</u> for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

Item a:

At the null hypothesis, it is <u>tested if the mean is of 7.4 minutes</u>, that is:

H_0: \mu = 7.4

At the alternative hypothesis, it is <u>tested if the mean is lower than 7.4 minutes</u>, that is:

H_1: \mu < 7.4

We have the <u>standard deviation for the population</u>, hence, the z-distribution is used.

The test statistic is given by:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

The parameters are:

  • \overline{x} is the sample mean.
  • \mu is the value tested at the null hypothesis.
  • \sigma is the standard deviation of the sample.
  • n is the sample size.

For this problem, the values of the <em>parameters </em>are: \overline{x} = 7.1, \mu = 7.4, \sigma = 1.2, n = 36.

Hence, the value of the <em>test statistic</em> is:

z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{7.1 - 7.4}{\frac{1.2}{\sqrt{36}}}

z = -1.5

Using a z-distribution calculator, the p-value is of 0.0668.

Also using a calculator, considering a <u>left-tailed test</u>, as we are testing if the mean is less than a value, the critical value with a <u>significance level of 0.1</u> is of z^{\ast} = -1.28.

Item b:

Since the <u>test statistic is less than the critical value</u> for the left-tailed test, there is enough evidence to conclude that the null hypothesis will be rejected.

You can learn more about the use of the z-distribution to test an hypothesis at brainly.com/question/16313918

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2 years ago
Suppose you have $10,000 to invest. Which of the two rates would yield the larger amount in 4 years. 7% compounded quarterly or
GalinKa [24]
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2)\ \ \ 6.94\%\ daily\\\\ \ \Rightarrow\ \  \frac{1}{365} \cdot6.94\% \approx0.019\%\ \ annually\ \ \Rightarrow\ \ p=0.019\\\\ daily\ \Rightarrow\  365\ times\ annually\ \Rightarrow\ 1420\ times\ in\ 4\ years\ \Rightarrow\ n=1420\\\\Sum(6.94\%)=\$10,000\cdot(1+ \frac{0.019}{100})^{1420}=\\ \\.\ \ \ \ \ \ \ \ \ \ \ \ =\$10,000\cdot(1+0,00019)^{1420}\approx\$13096.69\\---------------------------\\\$13,199.29 > \$13,096.69\\\\Ans.\ the\ larger\ amount\ gives\ the\ compounded\ quarterly.
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Step-by-step explanation:

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