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nikklg [1K]
2 years ago
5

Please help me with the below question.

Mathematics
1 answer:
tresset_1 [31]2 years ago
8 0

We have the following three conclusions about the <em>piecewise</em> function evaluated at x = 14.75:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

<h3>How to determinate the limit in a piecewise function</h3>

In a <em>piecewise</em> function, the limit for a given value exists when the two <em>lateral</em> limits are the same and, thus, continuity is guaranteed. Otherwise, the limit does not exist.  

According to the definition of <em>lateral</em> limit and by observing carefully the figure, we have the following conclusions:

  1. \lim_{t \to 14.75^{-}} f(t) = 66.
  2. \lim_{t \to 14.75^{+}} f(t) = 10.
  3. \lim_{t \to 14.75} f(t) does not exist as \lim_{t \to 14.75^{-}} f(t) \ne  \lim_{t \to 14.75^{+}} f(t).

To learn more on piecewise function: brainly.com/question/12561612

#SPJ1

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Answer:

72 yd / min

Step-by-step explanation:

The first thing is to fully calculate the distance traveled, each lap is 200 yards and how 6 laps would be:

200 * 6 = 1200

Now, let's divide the race into how the statement tells us:

1200 * 2/3 = 800

1200 * 1/3 = 400

That is, in the first 800 yards it goes to 80 yd / min and then in the remaining 400 yards it goes to 60 yd / min, let's calculate the time Rhea lasted:

800/80 = 10 min

400/60 = 6,667 min

Which means that in total it would be:

10 + 6,667 = 16,667

In other words, Rhea took 16,667 minutes to travel 1,200 yards, so the speed would be:

1200 / 16,667 = 72

Therefore the average Rhea speed was 72 yd / min

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3 years ago
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zavuch27 [327]
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Answer:

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Step-by-step explanation:

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3 years ago
Find xif 4; 4+2×;4+4× are in Geometric sequences​
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Given:

4,4+2x,4+4x are in geometric sequences​.

To find:

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Solution:

If a, b, c are in geometric sequences​, then

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It is given that 4,4+2x,4+4x are in geometric sequences​. By using (i), we get

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4x^2=0

x^2=0

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