Answer:my
The height of the stack will be 9.15×10^20_m
Or 9.15×10^17_Km
Which is 6 billion times more more than the distance to the sun
Or 22.9 million times further than the star Proxima Centauri
Step-by-step explanation:
Given
Avogadro's number = 6.02×10^23 particles
And the thickness of a penny = 1.52_mm
The height of the stack will be
1.52 × 6.02 ×10^23 = 9.15×10^23_mm 9.15×10^20_m
Answer:
Step-by-step explanation:
Dhcjfti
Answer: He still owns 64% of the Mr.Williams' original parking.
Step-by-step explanation:
Let x = Area of the original parking plot.
First he sold 20% of his lot to neighbor .
Sold plot = 20% of x = 0.20x [Replace 'of' by '×' and divide number by 100 to remove %]
Reminder= x-0.20x= (1-0.20)x=0.80x
Again he sold 20% of the remainder .
Sold plot = 20% of (0.80x) = 0.20 (0.80x)
= 0.16x
Remainder plot = 0.80x-0.16x= 0.64x
Percent of Mr.Williams' original parking lot does he still own = 
Hence, he still owns 64% of the Mr.Williams' original parking.
Answer:
When Ø = 300°, Ø = 60 degrees.
When Ø = 225°, Ø = 45 degrees.
When Ø = 480°, Ø = 60 degrees.
When Ø = -210°, Ø = 30 degrees.
Step-by-step explanation:
Reference angles are in Quadrant I (0° to 90°).
1. Find 300° (Quadrant IV) on the unit circle. Since it's in Quadrant IV, you use 360 - 300 = 60° to get your answer.
2. Find 225° (Quadrant III) on the unit circle. Since it's in Quadrant III, you use 225 - 180 = 45° to get your answer.
3. The angle 480° is not on the unit circle. To find its corresponding angle between 0° and 360°, use 480 - 360 = 120°. Then, find 120° (Quadrant II) on the unit circle. Since it's in Quadrant II, you use 180 - 120 = 60° to get your answer.
4. The angle -210° is not on the unit circle. To find its corresponding angle between 0° and 360°, use -210 + 360 = 150°. Then, find 150° (Quadrant II) on the unit circle. Since it's in Quadrant II, you use 180 - 150 = 30° to get your answer.